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HCF of co-prime numbers 4 and 15 was found as follows by factorisation:
$4 = 2 \times 2$ and $15 = 3 \times 5$ since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?
Given:
$4 = 2 \times 2$ and $15 = 3 \times 5$ since there is no common prime factor, so HCF of 4 and 15 is 0.
To do:
We have to find whether the answer is correct.
Solution:
$4=2\times2\times1$
$15=3\times5\times1$
Here,
The HCF of 4 and 15 is 1.
The given answer is not correct.
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