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Get the last element from a Sorted Set in Java
To create a Sorted Set, firstly create a Set −
Set<Integer> s = new HashSet<Integer>();
Add elements to the above set −
int a[] = {77, 23, 4, 66, 99, 112, 45, 56, 39, 89}; Set<Integer> s = new HashSet<Integer>(); try { for(int i = 0; i < 5; i++) { s.add(a[i]); }
After that, use TreeSet class to sort −
TreeSet sorted = new TreeSet<Integer>(s);
Get the last element, using the last() method −
System.out.println("
Last element of the sorted set = "+ (Integer)sorted.last());
The following is the code to get the last element from a Sorted Set in Java −
Example
import java.util.*; public class Demo { public static void main(String args[]) { int a[] = {77, 23, 4, 66, 99, 112, 45, 56, 39, 89}; Set<Integer> s = new HashSet<Integer>(); try { for(int i = 0; i < 5; i++) { s.add(a[i]); } System.out.println(s); TreeSet sorted = new TreeSet<Integer>(s); System.out.println("Sorted list = "); System.out.println(sorted); System.out.println("
Last element of the sorted set = "+ (Integer)sorted.last()); } catch(Exception e) {} } }
Output
[66, 99, 4, 23, 77] Sorted list = [4, 23, 66, 77, 99] Last element of the sorted set = 99
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