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Generate a Hermite series with given complex roots in Python
To generate a Hermite series with given complex roots, use the hermite.hermfromroots() method in Python Numpy. The method returns a 1-D array of coefficients. If all roots are real then out is a real array, if some of the roots are complex, then out is complex even if all the coefficients in the result are real. The parameter roots are the sequence containing the roots.
Steps
At first, import the required library −
from numpy.polynomial import hermite as H
To generate a Hermite series with given complex roots, use the hermite.hermfromroots() method −
j = complex(0,1)
print("Result...\n",H.hermfromroots((-j, j)))Get the datatype −
print("\nType...\n",H.hermfromroots((-j, j)).dtype)Get the shape −
print("\nShape...\n",H.hermfromroots((-j, j)).shape)Example
from numpy.polynomial import hermite as H
# To generate a Hermite series with given complex roots, use the hermite.hermfromroots() method in Python Numpy.
# The method returns a 1-D array of coefficients. If all roots are real then out is a real array, if some of the roots are complex, then out is complex even if all the coefficients in the result are real.
# The parameter roots are the sequence containing the roots.
j = complex(0,1)
print("Result...\n",H.hermfromroots((-j, j)))
# Get the datatype
print("\nType...\n",H.hermfromroots((-j, j)).dtype)
# Get the shape
print("\nShape...\n",H.hermfromroots((-j, j)).shape)Output
Result... [1.5 +0.j 0. +0.j 0.25+0.j] Type... complex128 Shape... (3,)
Updated on: 04-Mar-2022
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