Five square flower beds each of sides $ 1 \mathrm{~m} $ are dug on a piece of land $ 5 \mathrm{~m} $ long and 4 $ \mathrm{m} $ wide. What is the area of the remaining part of the land?
Given:
Five square flower beds each of sides $1\ m$ are dug on a piece of land $5\ m$ long and $4\ m$ wide.
To do:
We have to find the area of the remaining part of the land.
Solution:
We know that,
Area of a square of side $s$ is $s^2$.
Therefore,
The area of the one square flower bed$=( 1\ m)^2$
$=1\ m^2$
The area of the five square flower beds $=5\times1\ m^2$
$=5\ m^2$
The area of the land on which the square flower beds dug $= 5\ m\times4\ m$
$=20\ m^2$
We have to subtract the area of the land on which the flower beds are dug from the area of square flower beds to get the area of the remaining part of the land.
The area of the remaining part of the land$= 20\ m^2-5\ m^2$
$= 15\ m^2$
The area of the remaining part of the land is $15\ m^2$.
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