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Finding sort order of string in JavaScript
We are required to write a JavaScript function that takes in a string and checks whether it is sorted or not.
For example:
isSorted('adefgjmxz') // true
isSorted('zxmfdba') // true
isSorted('dsfdsfva') // falseTherefore, let’s write the code for this function −
Example
The code for this will be −
const str = 'abdfhlmxz';
const findDiff = (a, b) => a.charCodeAt(0) - b.charCodeAt(0);
const isStringSorted = (str = '') => {
if(str.length < 2){
return true;
};
let res = ''
for(let i = 0; i < str.length-1; i++){
if(findDiff(str[i+1], str[i]) > 0){
res += 'u';
}else if(findDiff(str[i+1], str[i]) < 0){
res += 'd';
};
if(res.indexOf('u') && res.includes('d')){
return false;
};
};
return true;
};
console.log(isStringSorted(str));Output
The output in the console will be −
true
Updated on: 21-Oct-2020
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