Find the sum :
(a) $ (-7)+(-9)+4+16 $
(b) $(37) + (– 2) + (– 65) + (– 8)$

To do :

We have to find the given sums.

Solution :

We know that,

$(+) \times (-) = (-)$

$(+) \times (+) = (+)$

$(-) \times (-) = (+)$

$(-) \times (+) = (-)$

(a) $(-7)+(-9)+4+16= -7-9+4+16$

$=-(7+9)+(4+16)$

$=-16+20$

$=20-16$

$= 4$

Therefore,

\( (-7)+(-9)+4+16=4 \)

(b) $(37)+(-2)+(-65)+(-8)= 37-2-65-8$

$=37-(2+65+8)$

$=37-75$

$=-(75-37)$

$= -38$

Therefore,

$(37)+(-2)+(-65)+(-8)=-38$

Tutorialspoint

Updated on: 10-Oct-2022

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