Find the roots of the following quadratic equations by factorisation:
$2x^2 – x + \frac{1}{8} = 0$

Given:

$2x^2 – x + \frac{1}{8} = 0$

To do:

We have to find the roots of the given quadratic equation.

Solution:

$2x^2 – x + \frac{1}{8} = 0$

$\frac{8(2x^2)-8(x)+1}{8}=0$

$16x^2-8x+1=0(8)$

$16x^2-8x+1=0$

$16x^2-4x-4x+1=0$

$4x(4x-1)-1(4x-1)=0$

$(4x-1)(4x-1)=0$

$4x-1=0$ or $4x-1=0$

$4x=1$ or $4x=1$

$x=\frac{1}{4}$ or $x=\frac{1}{4}$

Hence, the roots of the given quadratic equation are $\frac{1}{4}$ and $\frac{1}{4}$.

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Updated on: 10-Oct-2022

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