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Find the product:
$(i)$. $\frac{9}{2}\times(-\frac{7}{4})$
$(ii)$. $\frac{3}{10}\times(-9)$
$(iii)$. $-\frac{6}{5}\times\frac{9}{11}$
$(iv)$. $\frac{3}{7}\times(-\frac{2}{5})$
$(v)$. $\frac{3}{11}\times\ \frac{2}{5}$
$(vi)$. $\frac{3}{-5}\times(-\frac{5}{3})$
Given:
$(i)$. $\frac{9}{2}\times(-\frac{7}{4})$
$(ii)$. $\frac{3}{10}\times(-9)$
$(iii)$. $-\frac{6}{5}\times\frac{9}{11}$
$(iv)$. $\frac{3}{7}\times(-\frac{2}{5})$
$(v)$. $\frac{3}{11}\times\ \frac{2}{5}$
$(vi)$. $\frac{3}{-5}\times(-\frac{5}{3})$
To do: To find the product of the given expression.
Solution:
$(i)$. $\frac{9}{2}\times(-\frac{7}{4})$
$=\frac{9\times(-7)}{2\times4}$
$=-\frac{63}{8}$
$=-7\frac{7}{8}$
$(ii)$. $\frac{3}{10}\times(-9)$
$=-\frac{27}{10}$
$=-2\frac{7}{10}$
$(iii)$. $-\frac{6}{5}\times\frac{9}{11}$
$=\frac{(-6)\times9}{5\times11}$
$=-\frac{54}{55}$
$(iv)$. $\frac{3}{7}\times(-\frac{2}{5})$
$=\frac{3\times(-2)}{7\times5}$
$=-\frac{6}{35}$
$(v)$. $\frac{3}{11}\times\ \frac{2}{5}$
$=\frac{3\times2}{11\times5}$
$=\frac{6}{55}$
$(vi)$. $\frac{3}{-5}\times(-\frac{5}{3})$
$=\frac{3\times(-5)}{(-5)\times3}$
$=\frac{-15}{-15}$
$=1$
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