Find the perimeter of a triangle with sides measuring \( 10 \mathrm{~cm}, 14 \mathrm{~cm} \) and \( 15 \mathrm{~cm} \).
Given:
Sides of the triangle are $10\ cm,14\ cm$ and $15\ cm$.
To do:
We have to find the perimeter of the triangle.
Solution:
We know that,
The perimeter of a triangle is defined as the sum of the lengths of all three sides.
Therefore,
The perimeter of the triangle $= 10\ cm+14\ cm+15\ cm$
$ =39\ cm$
The perimeter of the triangle is $39\ cm$.
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