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Find the only missing number in a sorted array using C++
In this problem, we are given an arr[] of size N containing values from 1 to N with one value missing in the array. Our task is to find the only missing number in a sorted array.
Let’s take an example to understand the problem,
Input
arr[] = {1, 2, 3, 5, 6, 7}Output
4
Solution Approach
A simple solution to the problem is by traversing the sorted array linearly. And then check for the missing value using the fact that arr[i] = (i + 1).
Example 1
Program to illustrate the working of our solution
#include <iostream>
using namespace std;
int findMissingValArray(int arr[], int N){
for(int i = 0; i < N; i++){
if(arr[i] != (i+1))
return (i+1);
}
return -1;
}
int main(){
int arr[] = {1, 2, 3, 4, 6};
int N = sizeof(arr)/sizeof(arr[0]);
cout<<"The missing value from the array is "<<findMissingValArray(arr, N);
return 0;
}Output
The missing value from the array is 5
Another approach to solve the problem is using binary search and checking the value at mid. If the value at mid is mid+1 and value at (mid - 1) is (mid) then we will traverse the left subarray and vise versa.
Example 2
Program to illustrate the working of our solution
#include <iostream>
using namespace std;
int findMissingValArray(int arr[], int N){
int s = 0, e = N - 1;
while (s <= e) {
int mid = (s + e) / 2;
if (arr[mid] != mid + 1 && arr[mid - 1] == mid)
return (mid + 1);
if (arr[mid] != (mid + 1))
e = (mid - 1);
else
s = (mid + 1);
}
return -1;
}
int main(){
int arr[] = {1, 2, 3, 4, 6};
int N = sizeof(arr)/sizeof(arr[0]);
cout<<"The missing value from the array is "<<findMissingValArray(arr, N);
return 0;
}Output
The missing value from the array is 5
Updated on: 11-Feb-2022
1K+ Views
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