Find the number of spectators standing in the stadium at time t in Python

There are n number of spectators in the stadium, and they are labeled from 1 to n. Now follow these cases −

• At time t₁, the first spectator stands.

• At time t₂, the second spectator stands.

• …

• At time t_k, the k-th spectator stands.

• At time t_{k + 1}, the (k + 1)-th spectator stands and the first spectator sits.

• At time t_{k + 2}, the (k + 2)-th spectator stands and the second spectator sits.

• …

• At time t_n, the n-th spectator stands and the (n – k)-th spectator sits.

• At time t_{n + 1}, the (n + 1 – k)-th spectator sits.

• …

• At time t_{n + k}, the n-th spectator sits.

So, if the input is like n = 11, k = 6, t = 4, then the output will be 4 as at time t1, 1st spectator stands, then at time t2, 2nd spectator stands after that at time t3, 3rd spectator stands, and finally at time t4, 4th spectator stands. In this way the result is 4 as there are 4 spectators standing in total.

To solve this, we will follow these steps −

• if t <= k, then

  • return t

• otherwise when t <= n, then

  • return k

• otherwise,

  • res := t - n

  • res := k - res

• return res

Example

Let us see the following implementation to get better understanding −

 Live Demo

def how_many_stand(n, k, t) :
   if (t <= k) :
      return t
   elif (t <= n) :
      return k
   else :
      res = t - n
      res = k - res
      return res
n = 11
k = 6
t = 4
print(how_many_stand(n, k, t))

Input

11, 6, 4

Output

4

Arnab Chakraborty

Updated on: 27-Aug-2020

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