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Find:
$(i).\ 0.4 \div 2$
$(ii).\ 0.35 \div 5$
$(iii).\ 2.48 \div 4$
$(iv).\ 65.4 \div 6$
$(v).\ 651.2 \div 4$
$(vi).\ 14.49 \div 7$
$(vii).\ 3.96 \div 4$
$(viii).\ 0.80 \div 5$
To do:
We have to find
(i) $0.4 \div 2$
(ii) $0.35 \div 5$
(iii) $2.48 \div 4$
(iv) $65.4 \div 6$
(v) $651.2 \div 4$
(vi) $14.49 \div 7$
(vii) $3.96 \div 4$
(viii) $0.80 \div 5$
Solution:
We know that,
On dividing a decimal by $10^n$, the decimal point shifts to the left by $n$ places.
$\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}$
Therefore,
(i) $0.4 \div 2=\frac{4}{10}\div2$
$=\frac{4}{10}\times\frac{1}{2}$
$=\frac{4\times1}{10\times2}$
$=\frac{2}{10}$
$=0.2$
(ii) $0.35 \div 5=\frac{35}{100}\div5$
$=\frac{35}{100}\times\frac{1}{5}$
$=\frac{35\times1}{100\times5}$
$=\frac{7}{100}$
$=0.07$
(iii) $2.48 \div 4=\frac{248}{100}\div4$
$=\frac{248}{100}\times\frac{1}{4}$
$=\frac{62}{100}$
$=0.62$
(iv) $65.4 \div 6=\frac{654}{10}\div6$
$=\frac{654}{10}\times\frac{1}{6}$
$=\frac{109}{10}$
$=10.9$
(v) $651.2 \div 4=\frac{6512}{10}\times\frac{1}{4}$
$=\frac{6512\times1}{10\times4}$
$=\frac{1628}{10}$
$=162.8$
(vi) $14.49 \div 7=\frac{1449}{100}\times\frac{1}{7}$
$=\frac{1449\times1}{100\times7}$
$=\frac{207}{100}$
$=2.07$
(vii) $3.96 \div 4=\frac{396}{100}\times\frac{1}{4}$
$=\frac{396\times1}{100\times4}$
$=\frac{99}{100}$
$=0.99$
(viii) $0.80 \div 5=\frac{80}{100}\times\frac{1}{5}$
$=\frac{80\times1}{100\times5}$
$=\frac{16}{100}$
$=0.16$