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Find 2^(2^A) % B in C++
In this tutorial, we are going to write a program to evaluate the equation 2^(2^A) % B.
We are going to find the value of the equation using a recursive function. Let's see the steps to solve the problem.
Write a recursive function that takes 2 arguments A and B.
If A is 1, then return 4 % B as 2^(2^1) % B = 4 % B.
Else recursively call the function with A-1 and b.
Return the result^2%B.
Print the solution
Example
Let's see the code.
#include <bits/stdc++.h>
using namespace std;
long long solveTheEquation(long long A, long long B) {
// 2^(2^1) % B = 4 % B
if (A == 1) {
return (4 % B);
}
else {
long long result = solveTheEquation(A - 1, B);
return result * result % B;
}
}
int main() {
long long A = 37, B = 467;
cout << solveTheEquation(A, B) << endl;
return 0;
}Output
If you execute the above code, then you will get the following result.
113
Conclusion
If you have any queries in the tutorial, mention them in the comment section.
Updated on: 01-Feb-2021
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