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Explain, why $∆ABC ≅ ∆FED$.
Given: Two triangles $∆ABC$ and $∆FED$.
To do: To explain that $∆ABC ≅ ∆FED$.
Solution:
Given $\angle A\cong\angle F$
$BC=ED$
$\angle B=\angle E$
In $\triangle ABC$ and $\triangle FED$
$\angle B=\angle E=90^{\circ}$
$\angle A=\angle F$
$BC=ED$
Therefore, $\triangle ABC\cong\triangle FED$ [RHS congruence rule]
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