Draw rough sketches for the following:
$(a)$ In ∆ABC, BE is a median.
$(b)$ In ∆PQR, PQ and PR are altitudes of the triangle.
$(c)$ In ∆XYZ, YL is an altitude in the exterior of the triangle.

To do:

We have to draw rough sketches for the following:

(a) In $\triangle ABC, BE$ is a median.

(b) In $\triangle PQR, PQ$ and $PR$ are altitudes of the triangle.

(c) In $\triangle XYZ, YL$ is an altitude in the exterior of the triangle.

Solution :

(a)

A median of a triangle is a line segment joining a vertex to the mid-point of the side opposite side.

In \( \triangle \mathrm{ABC}, \mathrm{BE} \) is the median.

(b) An altitude of a triangle is the perpendicular drawn from the vertex of the triangle to the opposite side.

$\Delta PQR$ is a right-angled triangle in which $PQ$ and $QR$ are altitudes.

(c) 

$\Delta XYZ$ is an obtuse-angled triangle $YL$ is an altitude in the exterior of the triangle.

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Updated on: 10-Oct-2022

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