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Decimal.ToInt32() Method in C#
The Decimal.ToInt32() method in C# is used to convert the value of the specified Decimal to the equivalent 32-bit signed integer.
Syntax
Following is the syntax −
public static int ToInt32 (decimal val);
Above, Val is the decimal number to convert.
Example
Let us now see an example to implement the Decimal.ToInt32() method −
using System;
public class Demo {
public static void Main(){
Decimal val1 = 0.001m;
Decimal val2 = 1.000m;
Console.WriteLine("Decimal 1 = "+val1);
Console.WriteLine("Decimal 2 = "+val2);
int res1 = Decimal.ToInt32(val1);
int res2 = Decimal.ToInt32(val2);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res1);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res2);
}
}Output
This will produce the following output −
Decimal 1 = 0.001 Decimal 2 = 1.000 32-bit signed integer (value1) (Decimal to signed integer) = 0 32-bit signed integer (value1) (Decimal to signed integer) = 1
Example
Let us now see another example to implement the Decimal.ToInt32() method −
using System;
public class Demo {
public static void Main(){
Decimal val1 = -3.578m;
Decimal val2 = 9.352m;
Console.WriteLine("Decimal 1 = "+val1);
Console.WriteLine("Decimal 2 = "+val2);
int res1 = Decimal.ToInt32(val1);
int res2 = Decimal.ToInt32(val2);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res1);
Console.WriteLine("32-bit signed integer (value1) (Decimal to signed integer) = "+res2);
}
}Output
This will produce the following output −
Decimal 1 = -3.578 Decimal 2 = 9.352 32-bit signed integer (value1) (Decimal to signed integer) = -3 32-bit signed integer (value1) (Decimal to signed integer) = 9
Updated on: 12-Nov-2019
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