C++ Unordered_set::swap() function
The C++ std::unordered_set::swap() function is used to exchange the contents of the unordered_set with others. If both the unordered_sets have the same contents, it does nothing; otherwise, exchange the contents of the unordered_sets with another unordered_set. The return type of this function is void which implies that it does not return any value.
Syntax
Following is the syntax of std::unordered_set::swap() function −
void swap ( unordered_set& other);
Parameters
- other − It is another container to exchange the contents with.
Return Value
This function does not return any value.
Example 1
Let's look at the following example, where we are going to exchange the contents of the num_set1 with the contents of the num_set2.
#include<iostream>
#include<string>
#include<unordered_set>
using namespace std;
int main () {
//create unordered_sets
unordered_set<int> num_set1 = {1, 2, 3, 4, 5};
unordered_set<int> num_set2 = {6, 7, 8, 9, 10};
cout<<"Contents of the num_set1 before swap operation: "<<endl;
for(int n1 : num_set1){
cout<<n1<<endl;
}
cout<<"Contents of the num_set2 before swap operation: "<<endl;
for(int n2 : num_set2){
cout<<n2<<endl;
}
//using the swap() function
num_set1.swap(num_set2);
cout<<"Contents of the num_set1 after swap operation: "<<endl;
for(int n1 : num_set1){
cout<<n1<<endl;
}
cout<<"Contents of the num_set2 after swap operation: "<<endl;
for(int n2 : num_set2){
cout<<n2<<endl;
}
}
Output
If we run the above code it will generate the following output −
Contents of the num_set1 before swap operation: 5 4 3 2 1 Contents of the num_set2 before swap operation: 10 9 8 7 6 Contents of the num_set1 after swap operation: 10 9 8 7 6 Contents of the num_set2 after swap operation: 5 4 3 2 1
Example 2
Consider the another scenario, where we are going to consider the unordered_sets of char type and applying the swap() function.
#include<iostream>
#include<string>
#include<unordered_set>
using namespace std;
int main () {
//create unordered_sets
unordered_set<char> char_set1 = {};
unordered_set<char> char_set2 = {'a', 'b', 'c', 'd'};
cout<<"Size of the char_set1 before swap operation: "<<char_set1.size()<<endl;
cout<<"Contents of the char_set2 before swap operation: "<<endl;
for(char c2 : char_set2){
cout<<c2<<endl;
}
//using the swap() function
char_set1.swap(char_set2);
cout<<"Contents of the char_set1 after swap operation: "<<endl;
for(char c1 : char_set1){
cout<<c1<<endl;
}
cout<<"Size of the char_set2 after the swap operation: "<<char_set2.size();
}
Output
Following is the output of the above code −
Size of the char_set1 before swap operation: 0 Contents of the char_set2 before swap operation: d c b a Contents of the char_set1 after swap operation: d c b a Size of the char_set2 after the swap operation: 0
Example 3
In the following example, we are going to consider the unordered_set of string type and applying the swap() function to exchange the contents of the unordered_set.
#include<iostream>
#include<string>
#include<unordered_set>
using namespace std;
int main () {
//create unordered_sets
unordered_set<string> str_set1 = {"Red", "Blue", "Yellow", "White"};
unordered_set<string> str_set2 = {"Apple", "Banana", "Mango", "Orange"};
cout<<"Contents of the str_set1 before swap operation: "<<endl;
for(string s1 : str_set1){
cout<<s1<<endl;
}
cout<<"Content of the str_set2 before swap operation: "<<endl;
for(string s2 : str_set2){
cout<<s2<<endl;
}
//using swap() operation
str_set1.swap(str_set2);
cout<<"Contents of the str_set1 after swap operation: "<<endl;
for(string s1 : str_set1){
cout<<s1<<endl;
}
cout<<"Content of the str_set2 after swap operation: "<<endl;
for(string s2 : str_set2){
cout<<s2<<endl;
}
}
Output
Output of the above code is as follows −
Contents of the str_set1 before swap operation: White Yellow Blue Red Content of the str_set2 before swap operation: Mango Banana Orange Apple Contents of the str_set1 after swap operation: Mango Banana Orange Apple Content of the str_set2 after swap operation: White Yellow Blue Red