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C++ program to find the sum of the series (1/a + 2/a^2 + 3/a^3 + … + n/a^n)
In this tutorial, we will be discussing a program to find the sum of the given series (1/a + 2/a^2 + 3/a^3 + … + n/a^n).
For this, we will be given with the value of n and our task is to add up every term starting from the first one to find the sum of the given series.
Example
#include <iostream> #include <math.h> using namespace std; //calculating the sum of the series float calc_sum(int a, int n) { int i; float sum = 0; for (i = 1; i <= n; i++) sum += (i/ pow(a, i)); return sum; } int main() { int a = 3, n = 4; float res = calc_sum(a,n); cout << res << endl; return 0; }
Output
0.716049
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