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C++ Program for cube sum of first n natural numbers?
Positive integers 1, 2, 3, 4... are known as natural numbers.
This program takes a positive integer from the user ( suppose user-entered n ) then, this program displays the value of 13+23+33+....+n3.
Input: n = 3 Output: 36
Explanation
13+23+33 = 1 +8+27 = 36
This program takes a positive integer from user( suppose user entered n ) then, this program displays the value of 13+23+33+....+n3.
Example
#include <iostream>
using namespace std;
int main() {
int n = 3;
int sum = 0;
for (int x=1; x<=n; x++)
sum += x*x*x;
cout << sum;
return 0;
}
Updated on: 20-Aug-2019
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