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C++ code to find xth element after removing numbers
Suppose we have two numbers n and x. First n natural numbers are written on a blackboard. In ith (i starts from 1) operation, we remove ith number from the blackboard. When there are less than i numbers, we stop removal task. We have to find x-th remaining number after stopping removal.
So, if the input is like n = 69; x = 6, then the output will be 12. In first operation, i = 1, so remove 1, then in second operation i = 2, but the sequence is 2, 3, 4 ... so second number is 3, remove 3, like this finally the xth number is 12.
Steps
To solve this, we will follow these steps −
return 2 * x
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
int solve(int n, int x){
return 2 * x;
}
int main(){
int n = 69;
int x = 6;
cout << solve(n, x) << endl;
}Input
69, 6
Output
12
Updated on: 15-Mar-2022
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