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C++ code to count number of weight splits of a number n
Suppose we have a number n. We can split n as a nonincreasing sequence of positive integers, whose sum is n. The weight of a split is the number of elements in the split that are equal to the first element. So, the weight of the split [1,1,1,1,1] is 5, the weight of the split [5,5,3,3,3] is 2 and the weight of the split [9] equals 1. We have to find out the number of different weights of n's splits.
So, if the input is like n = 7, then the output will be 4, because possible weights are [7], [3, 3, 1], [2, 2, 2, 1], [1, 1, 1, 1, 1, 1, 1]
Steps
To solve this, we will follow these steps −
return (n / 2 + 1)
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
int solve(int n){
return (n / 2 + 1);
}
int main(){
int n = 7;
cout << solve(n) << endl;
}Input
7
Output
4
Updated on: 30-Mar-2022
124 Views
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