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Count number of trailing zeros in Binary representation of a number using Bitset in C++
Given an integer num as input. The goal is to find the number of trailing zeroes in the binary representation of num using bitset.
A bitset stores the bits 0s and 1s in it. It is an array of bits.
For Example
Input
num = 10
Output
Count of number of trailing zeros in Binary representation of a number using Bitset are: 1
Explanation
The number 10 in binary is represented as 1010 so trailing zeroes in it is 1.
Input
num = 64
Output
Count of number of trailing zeros in Binary representation of a number using Bitset are: 6
Explanation
The number 64 in binary is represented as 10000000 so trailing zeroes in it is 6.
Approach used in the below program is as follows −
In this approach we are using bitset. We will set the bitset with num using |. Now traverse bitset using for loop, as soon as the first 1 is encountered then break the loop otherwise increment count for trailing zeroes.
Take an integer num as input.
Function trailing_zeroes(int num) takes num and returns the count of number of trailing zeros in Binary representation of a number using Bitset.
Take the initial count as 0.
Take a bitset arr.
Set it with num as arr |=num.
Traverse arr using for loop from i=0 to i<64. If arr[i] is 0 then increment count else breaks the loop.
Return count as result at the end of loop.
Example
#include <bits/stdc++.h>
using namespace std;
int trailing_zeroes(int num){
int count = 0;
bitset<64> arr;
arr |= num;
for (int i = 0; i < 64; i++){
if (arr[i] == 0){
count++;
} else {
break;
}
}
return count;
}
int main(){
int num = 6;
cout<<"Count of number of trailing zeros in Binary representation of a number using Bitset are: "<<trailing_zeroes(num);
return 0;
}Output
If we run the above code it will generate the following output −
Count of number of trailing zeros in Binary representation of a number using Bitset are: 1
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