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Count and Print the alphabets having ASCII value in the range [l, r] in C++
We are given with a string of any length and the task is to calculate the count and print the alphabets in a string having ASCII value in the range [l,r]
ASCII value for character A-Z are given below
| A | B | C | D | E | F | G | H | I | J | K | L | M | N | O | P | Q | R | S |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 65 | 66 | 67 | 68 | 69 | 70 | 71 | 72 | 73 | 74 | 75 | 76 | 77 | 78 | 79 | 80 | 81 | 82 | 83 |
| T | U | V | W | X | Y | Z |
|---|---|---|---|---|---|---|
| 84 | 85 | 86 | 87 | 88 | 89 | 90 |
ASCII value for characters a-z are given below −
| a | b | c | d | e | f | g | h | i | j | k | l | m | n | o | p | q | r | s |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 9 7 | 9 8 | 9 9 | 10 0 | 10 1 | 10 2 | 10 3 | 10 4 | 10 5 | 10 6 | 10 7 | 10 8 | 10 9 | 11 0 | 11 1 | 11 2 | 11 3 | 11 4 | 11 5 |
| t | u | v | w | x | y | z |
|---|---|---|---|---|---|---|
| 116 | 117 | 118 | 119 | 120 | 121 | 122 |
For Example
Input − String str = “point First = 111, Last = 117 Output − characters in the given range are: p, o , t Count is: 3
Explanation − since p, o and t lies in the range of [111, 117] these characters will be counted.
Input − String str = “ABCZXY First = 65, Last = 70 Output − characters in the given range are: A, B, C Count is: 3
Explanation − since A, B and C lies in the range of [65, 70] these characters will be counted.
Approach used in the below program is as follows
Input the string, start and end values to create the range and store it in variables let’s say, str.
Calculate the length of the string using the length() function that will return an integer value as per the number of letters in the string including the spaces.
Take a temporary variable that will store the count of characters
Start the loop from i to 0 till i is less than the length of the string
Inside the loop, check if start is less than equals to str[i] and str[i] is less than equals to end
Now, increase the count by 1 if condition holds true and print str[i]
Return the count
Print the result
Example
#include <iostream>
using namespace std;
// Function to count the number of
// characters whose ascii value is in range [l, r]
int count_char(string str, int left, int right){
// Initializing the count to 0
int count = 0;
int len = str.length();
for (int i = 0; i < len; i++) {
// Increment the count
// if the value is less
if (left <= str[i] and str[i] <= right) {
count++;
cout << str[i] << " ";
}
}
// return the count
return count;
}
int main(){
string str = "tutorialspoint";
int left = 102, right = 111;
cout << "Characters in the given range";
cout << "\nand their count is " << count_char(str, left, right);
return 0;
}Output
If we run the above code it will generate the following output −
Characters in the given range and their count is o i l o i n 6
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