![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Construct $∆ABC$ such that $AB=2.5\ cm$, $BC=6\ cm$ and $AC=6.5\ cm$. Measure $\angle B$.
To do: To construct $∆ABC$ such that $AB=2.5\ cm$, $BC=6\ cm$ and $AC=6.5\ cm$ and measure $\angle B$.
Steps of construction -
- Let us draw a line segment $BC=6\ cm$.
- Assuming $B$ as the center, let us draw an arc of radius $2.5\ cm$.
- Assuming point $C$ as the center let us draw an arc of radius $6.5\ cm$.
- Both the arcs intersect each other at the point $A$.
- Now let us join $AB$ and $AC$.
Thus, $ABC$ is the required triangle that has been constructed.
![](/assets/questions/media/148618-63933-1658336228.png)
On measuring $\angle B$ with the help of a protractor we find that it is a right-angled triangle ABC, where $\angle B = 90^{\circ}$.
Advertisements