Choose the correct answer from the given four options in the following questions:
The zeroes of the quadratic polynomial $ x^{2}+99 x+127 $ are
(A) both positive
(B) both negative
,b>(C) one positive and one negative
(D) both equal
Given:
Quadratic polynomial $x^2+99x+127$.
To do:
We have to find the nature of the zeroes of the quadratic polynomial $x^2+99x+127$.
Solution:
In a quadratic expression $ax^2+bx+c$, if $a,\ b,\ c$ will have the same sign
then the both zeroes of the expression are negative
On comparing given expression $x^2+99x+127$ with $ax^2+bx+c$,
$a=1,\ b = 99,\ c = 127$
All have positive sign.
Therefore, both the zeroes of the given expression have negative sign.
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