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Check if a string contains only alphabets in Java using ASCII values
Let’s say we have set out inut string in myStr variable. Now loop through until the length of string and check for alphabets with ASCII values −
for (int i = 0; i < myStr.length(); i++) {
char c = myStr.charAt(i);
if (!(c >= 'A' && c <= 'Z') && !(c >= 'a' && c <= 'z')) {
return false;
}
return true;
}Following is an example to check if a string contains only alphabets in Java using ASCII values;
Example
class Main {
public static boolean checkAlphabet(String myStr) {
for (int i = 0; i < myStr.length(); i++) {
char c = myStr.charAt(i);
if (!(c >= 'A' && c <= 'Z') && !(c >= 'a' && c <= 'z')) {
return false;
}
}
return true;
}
public static void main(String[] args) {
String str1 = "Tom1";
System.out.println("String1 = " + str1);
System.out.println("Is String1 contains only alphabets? = " + checkAlphabet(str1));
String str2 = "Tim";
System.out.println("String2 = " + str2);
System.out.println("Is String2 contains only alphabets? = " + checkAlphabet(str2));
}
}Output
String1 = Tom1 Is String1 contains only alphabets? = false String2 = Tim Is String2 contains only alphabets? = true
Updated on: 20-Sep-2019
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