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Check if a large number is divisible by 2, 3 and 5 or not in C++
Here we will see how to check a number is divisible by 2, 3 and 5 or not. In this case the number is very large number. So we put the number as string.
A number will be divisible by 2, 3 and 5 if that number is divisible by LCM of 2,3 and 5. So the LCM of 2, 3, 5 is 30. We have to check the number is divisible by 30 or not. A number is divisible by 30 when it is divisible by 10 (last digit is 0) and divisible by 3 (sum of all digits is divisible by 3)
Example
#include <bits/stdc++.h>
using namespace std;
bool isDiv30(string num){
int n = num.length();
if(num[n - 1] != '0')
return false;
long sum = accumulate(begin(num), end(num), 0) - '0' * n;
if(sum % 3 == 0)
return true;
return false;
}
int main() {
string num = "353730746028908374890";
if(isDiv30(num)){
cout << "Divisible";
} else {
cout << "Not Divisible";
}
}Output
Divisible
Updated on: 27-Sep-2019
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