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Character class: subtraction - Java regular expressions
You can subtract one range from other and use it as new range. You can achieve this by using two variants of character classes i.e. negation and intersection.
For example the intersection of ranges [a-l] and [^e-h] gives you the characters a to l as rage subtracting the characters [e-h]
Example
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class RegexExample1 {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter input text: ");
String input = sc.nextLine();
String regex = "[a-l&&[^e-h]]";
//Creating a pattern object
Pattern pattern = Pattern.compile(regex);
//Matching the compiled pattern in the String
Matcher matcher = pattern.matcher(input);
int count =0;
while (matcher.find()) {
count++;
System.out.print(matcher.group()+" ");
}
System.out.println("Number of matched characters: "+count);
}
}Output
Enter input text: abcdefghijklmnopq a b c d i j k l Number of matched characters: 8
Updated on: 10-Jan-2020
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