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C Program to display the numbers in X pattern
Refer an algorithm given below for the C program to display the numbers in X pattern.
Algorithm
Step 1: Start Step 2: Declare variables Step 3: Read number of rows Step 4: for loop satisfies
- if(i==j || i+j==rows-1)
- print i+1
- Print " "
The logic to print numbers in X pattern is as follows −
for(i=0;i<rows;i++){ for(j=0;j<rows;j++){ if(i==j || i+j==rows-1){ printf("%d",i+1); }else{ printf(" "); } } printf("
"); }
Program
Following is the C program to display the numbers in X pattern −
#include<stdio.h> main(){ int i,j,rows; printf("Enter number of rows:
"); scanf("%d",&rows); for(i=0;i<rows;i++){ for(j=0;j<rows;j++){ if(i==j || i+j==rows-1){ printf("%d",i+1); }else{ printf(" "); } } printf("
"); } }
Output
When the above program is executed, it produces the following result −
Enter number of rows:10 1 1 2 2 3 3 4 4 55 66 7 7 8 8 9 9 10 10
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