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BitConverter.ToInt16() Method in C#
The BitConverter.ToInt16() method in C# is used to return a 16-bit signed integer converted from two bytes at a specified position in a byte array.
Syntax
The syntax is as follows −
public static short ToInt16 (byte[] val, int begnIndex);
Above, val is the byte array, whereas begnIndex is the beginning position within val.
Example
Let us now see an example −
using System;
public class Demo {
public static void Main(){
byte[] arr = { 0, 0, 7, 10, 18, 20, 25, 26, 32};
Console.WriteLine("Byte Array = {0} ", BitConverter.ToString(arr));
for (int i = 1; i < arr.Length - 1; i = i + 2) {
short res = BitConverter.ToInt16(arr, i);
Console.WriteLine("
Value = "+arr[i]);
Console.WriteLine("Result = "+res);
}
}
}Output
This will produce the following output −
Byte Array = 00-00-07-0A-12-14-19-1A-20 Value = 0 Result = 1792 Value = 10 Result = 4618 Value = 20 Result = 6420 Value = 26 Result = 8218
Example
Let us now see another example −
using System;
public class Demo {
public static void Main(){
byte[] arr = { 10, 20, 30};
Console.WriteLine("Byte Array = {0} ", BitConverter.ToString(arr));
for (int i = 1; i < arr.Length - 1; i = i + 2) {
short values = BitConverter.ToInt16(arr, i);
Console.WriteLine("
Value = "+arr[i]);
Console.WriteLine("Result = "+values);
}
}
}Output
This will produce the following output −
Byte Array = 0A-14-1E Value = 20 Result = 7700
Updated on: 03-Dec-2019
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