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BitConverter.ToDouble() Method in C#
The BitConverter.ToDouble() method in C# is used to return a double-precision floating-point number converted from eight bytes at a specified position in a byte array.
Synchronized
The syntax is as follows −
public static double ToDouble (byte[] val, int begnIndex);
Above, val is the byte array, whereas begnIndex is the beginning position within val.
Example
Let us now see an example −
using System;
public class Demo {
public static void Main(){
byte[] arr = { 0, 2, 5, 10, 20, 26, 34, 42, 50, 58, 66, 74, 82, 89, 97, 107, 115};
Console.WriteLine("Byte Array = {0} ", BitConverter.ToString(arr));
for (int i = 1; i < arr.Length - 7; i = i + 8) {
double values = BitConverter.ToDouble(arr, i);
Console.WriteLine("
Value = "+arr[i]);
Console.WriteLine("Result = "+values);
}
}
}Output
This will produce the following output −
Byte Array = 00-02-05-0A-14-1A-22-2A-32-3A-42-4A-52-59-61-6B-73 Value = 2 Result = 4.84667324189914E-67 Value = 58 Result = 9.57203245252997E+247
Example
Let us now see another example −
using System;
public class Demo {
public static void Main(){
byte[] arr = { 0, 3, 7, 10, 18, 20, 25, 26, 34};
Console.WriteLine("Byte Array = {0} ",
BitConverter.ToString(arr));
for (int i = 1; i < arr.Length - 7; i = i + 8) {
double values = BitConverter.ToDouble(arr, i);
Console.WriteLine("
Value = "+arr[i]);
Console.WriteLine("Result = "+values);
}
}
}Output
This will produce the following output −
Byte Array = 00-03-07-0A-12-14-19-1A-22 Value = 3 Result = 2.09001158167895E-144
Updated on: 03-Dec-2019
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