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About
Simple and Easy Learning
Tutorials Point originated from the idea that there exists a class of readers who respond better to online content and prefer to learn new skills at their own pace from the comforts of their drawing rooms.
The journey commenced with a single tutorial on HTML in 2006 and elated by the response it generated, we worked our way to adding fresh tutorials to our repository which now proudly flaunts a wealth of tutorials and allied articles on topics ranging from programming languages to web designing to academics and much more.
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Tutorialspoint has Published 24147 Articles
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Tutorialspoint
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Given:\( \frac{x}{3}+1=\frac{7}{15} \).To do: We have to solve the given equation.Solution:$\frac{x}{3}+1=\frac{7}{15}$We get,$\frac{x}{3}=\frac{7}{15}-1$$\frac{x}{3}=\frac{7-15}{15}$$\frac{x}{3}=\frac{-8}{15}$$x=\frac{-8\times3}{15}$$x=\frac{-8}{5}$The value of $x$ is $\frac{-8}{5}$.
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Tutorialspoint
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Given:\( 3 x=2 x+18 \).To do: We have to solve the given equation and check the result.Solution:$3x=2x+18$$3x-2x=18$$x=18$Substituting the value of $x$ in LHS, we get,$3x=3(18)$$=54$Substituting the value of $x$ in RHS, we get,$2x+18=2(18)+18$$=36+18$$=54$LHS $=$ RHSThe value of $x$ is $18$.
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Tutorialspoint
30 Views
Given:\( 5 t-3=3 t-5 \).To do: We have to solve the given equation and check the result.Solution:$5t-3=3t-5$$5t-3t=-5+3$$2t=-2$$t=\frac{-2}{2}$$t=-1$Substituting the value of $t$ in LHS, we get, $5t-3=5(-1)-3$$=-5-3$$=-8$Substituting the value of $t$ in RHS, we get, $3t-5=3(-1)-5$$=-3-5$$=-8$LHS $=$ RHSThe value of $t$ is $-1$. Read More
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Tutorialspoint
37 Views
Given:\( 5 x+9=5+3 x \).To do: We have to solve the given equation and check the result.Solution:$5x+9=5+3x$$5x-3x=5-9$$2x=-4$$x=\frac{-4}{2}$$x=-2$Substituting the value of $x$ in LHS, we get, $5x+9=5(-2)+9$$=-10+9$$=-1$Substituting the value of $x$ in RHS, we get, $5+3x=5+3(-2)$$=5-6$$=-1$LHS $=$ RHSThe value of $x$ is $-2$.Read More
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Tutorialspoint
28 Views
Given:\( 4 z+3=6+2 z \)To do: We have to solve the given equation and check the result.Solution:$4z+3=6+2z$$4z-2z=6-3$$2z=3$$z=\frac{3}{2}$Substituting the value of $z$ in LHS, we get, $4z+3=4(\frac{3}{2})+3$$=2(3)+3$$=6+3$$=9$Substituting the value of $z$ in RHS, we get, $6+2z=6+2(\frac{3}{2})$$=6+3$$=9$LHS $=$ RHSThe value of $z$ is $\frac{3}{2}$. Read More
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Tutorialspoint
31 Views
Given:\( 2 x-1=14-x \)To do: We have to solve the given equation and check the result.Solution:$2 x-1=14-x$$2x-(-x)=14+1$$2x+x=15$$3x=15$$x=\frac{15}{3}$$x=5$Substituting the value of $x$ in LHS, we get, $2x-1=2(5)-1$$=10-1$$=9$Substituting the value of $x$ in RHS, we get, $14-x=14-5$$=9$LHS $=$ RHSThe value of $x$ is $9$. Read More