Given:Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas.To do:We have to find who bought more.Solution:We know that, $1000\ g=1\ kg$According to the question, Weight of apples bought by Shyama $=5\ kg\ 300\ ... Read More

To do:We have to write the place value of 2 in the given decimal numbers.Solution:(i) $\underline{2}.56$$2$ is at ones place. Hence place value of $2$ is $2\times1=2$(ii) $\underline{2}1.37$$2$ is at tens place. Hence place value of $2$ is $2\times10=20$(iii) $10.\underline{2}5$$2$ is at tenths place. Hence place value of $2$ is ... Read More

To do:We have to write the given decimal numbers in the expanded form.Solution:(i) $20.03=2\times10+0\times1+0\times\frac{1}{10}+3\times\frac{1}{100}$(ii) $2.03=2\times1+0\times\frac{1}{10}+3\times\frac{1}{100}$(iii) $200.03=2\times100+0\times10+0\times1+0\times\frac{1}{10}+3\times\frac{1}{100}$(iv) $2.034=2\times1+0\times\frac{1}{10}+3\times\frac{1}{100}+4\times\frac{1}{1000}$

Given:(i) $200$ g   (ii) $3470$ g   (iii) $4$ kg $8$ gTo do:We have to express the weights in kg.Solution:$1000\ g =1\ kg$This implies, $1\ g = \frac{1}{1000}\ kg$Therefore, (i) $200 g$$200\ g = 200\times \frac{1}{1000}\ kg$$=\frac{200}{1000}\ kg$$=0.2\ kg$(ii) $3470\ g$$3470\ g=3470 \times \frac{1}{1000}\ kg$$3470\ g=\frac{3470}{1000}\ kg$$=3.47\ kg$(iii) $4\ kg\ 8\ ... Read More

To do :(i) We have to express $5\ cm$ in meter and kilometer. (ii) We have to express $35\ mm$ in $cm, m$ and $km$.Solution :(i) We know that, $1\ km = 1000\ m$ and $1\ m = 100\ cm$This implies, $1\ cm = \frac{1}{100}\ m = 0.01\ m$$1\ cm ... Read More

Given: (i) $7$ paise(ii) $7$ rupees $7$ paise(iii) $77$ rupees $77$ paise(iv) $50$ paise(v) $235$ paiseTo do: Here we have to express the given amounts as rupees using decimals.Solution:We know that, $Rs.\ 1=100$ paiseThis implies, $1$ paise $=Rs.\ \frac{1}{100}$So, (i) 7 paise$=Rs.\ \frac{7}{100}$$=Rs.\ 0.07$(ii) 7 rupees 7 paise$=Rs.\ (7+ \frac{7}{100})$$=Rs.\ (7+0.07)$$=Rs.\ ... Read More

Given:Given numbers are: (i) $0.5$ or $0.05$(ii) $0.7$ or $0.5$   (iii) $7$ or $0.7$(iv) $1.37$ or $1.49$   (v) $2.03$ or $2.30$   (vi) $0.8$ or $0.88$To do:We have to find the greater number in each of the given numbers.Solution:(i) $0.5$ or $0.05$$0.5$ or $0.05$$0.5=\frac{5}{10}$ or $0.05=\frac{5}{100}$On converting decimals them into like fractions, ... Read More

To do:We have to write the fractions representing the shaded portion.Solution:(i) There are four parts in total and 2 parts are shaded.Therefore, The fraction representing the shaded portion $= \frac{2}{4}$$= \frac{1}{2}$.(ii) There are nine parts in total and 8 parts are shaded.Therefore, The fraction representing the shaded portion $= \frac{8}{9}$(iii) ... Read More

To do :We have to find the given sums.Solution :We know that, $(+) \times (-) = (-)$$(+) \times (+) = (+)$$(-) \times (-) = (+)$$(-) \times (+) = (-)$(a) $137+(-354) = 137-354$$=-(354-137)$$= -217$Therefore, The sum of $137$ and $(-354)$ is $-217$.  (b) $-52+ 52 = 52-52$$= 0$Therefore, The sum of $-52$ and ... Read More

To do :We have to find the given sums.Solution :We know that, $(+) \times (-) = (-)$$(+) \times (+) = (+)$$(-) \times (-) = (+)$$(-) \times (+) = (-)$(a) $(-7)+(-9)+4+16= -7-9+4+16$$=-(7+9)+(4+16)$$=-16+20$$=20-16$$= 4$Therefore, \( (-7)+(-9)+4+16=4 \)(b) $(37)+(-2)+(-65)+(-8)= 37-2-65-8$$=37-(2+65+8)$$=37-75$$=-(75-37)$$= -38$Therefore, $(37)+(-2)+(-65)+(-8)=-38$ Read More