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Read the bar graph $(Fig\ 3.4)$ which shows the number of books sold by a bookstore during five consecutive years and answer the following questions:

$(i)$. About how many books were sold in 1989? 1990? 1992?
$(ii)$. In which year were about 475 books sold? About 225 books sold?
$(iii)$. In which years were fewer than 250 books sold?
$(iv)$. Can you explain how you would estimate the number of books sold in 1989?"

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Tutorialspoint

Updated on 10-Oct-2022 13:33:22

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To do:We have to read the bar graph which shows the number of books sold by a bookstore during five consecutive years and answer the given questions.Solution:(i) In 1989, about 175 books were sold. In 1990, about 475 books were sold. In 1992, about 225 books were sold.(ii) In 1990 about ... Read More

Write the numbers given in the following place value table in decimal form.
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Tutorialspoint

Updated on 10-Oct-2022 13:33:21

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To do:We have to write the given numbers in the place value table in decimal form.Solution:(a) $0\times100+0\times10+3\times1+2\times\frac{1}{10}+5\times\frac{1}{100}+0\times\frac{1}{1000}=0+0+3+\frac{2}{10}+\frac{5}{100}+0$$=3+0.2+0.05$$=3.25$(b) $1\times100+0\times10+2\times1+6\times\frac{1}{10}+3\times\frac{1}{100}+0\times\frac{1}{1000}=100+0+2+\frac{6}{10}+\frac{3}{100}+0$$=100+2+0.6+0.03$$=102.63$(c) $0\times100+3\times10+0\times1+0\times\frac{1}{10}+2\times\frac{1}{100}+5\times\frac{1}{1000}=0+30+0+0+\frac{2}{100}+\frac{5}{1000}$$=30+0.02+0.005$$=30.025$(d) $2\times100+1\times10+1\times1+9\times\frac{1}{10}+0\times\frac{1}{100}+2\times\frac{1}{1000}=200+10+1+\frac{9}{10}+0+\frac{2}{1000}$$=200+10+1+0.9+0.002$$=211.902$(e) $0\times100+1\times10+2\times1+2\times\frac{1}{10}+4\times\frac{1}{100}+1\times\frac{1}{1000}=0+10+2+\frac{2}{10}+\frac{4}{100}+\frac{1}{1000}$$=0+10+2+0.2+0.04+0.001$$=12.241$Read More

(a) The length of Ramesh's notebook is \( 9 \mathrm{~cm} 5 \mathrm{~mm} \). What will be its length in \( \mathrm{cm} \)?
(b) The length of a young gram plant is \( 65 \mathrm{~mm} \). Express its length in \( \mathrm{cm} \).

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Tutorialspoint

Updated on 10-Oct-2022 13:33:20

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To do:We have to find their length in \( \mathrm{cm} \).Solution:We know that, $1\ cm=10\ mm$This implies, $1\ mm=\frac{1}{10}\ cm=0.1\ cm$(a) $5\ mm=5\times0.1\ cm$$=0.5\ cm$Therefore, The length of Ramesh's notebook $=9\ cm+0.5\ cm$$=(9+0.5)\ cm$$=9.5\ cm$The length of Ramesh's notebook in \( \mathrm{cm} \) is $9.5\ cm$.(b) $65\ mm=65\times0.1\ cm$$=6.5\ cm$Therefore, ... Read More

Find the range of heights of any ten students of your class.

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Tutorialspoint

Updated on 10-Oct-2022 13:33:20

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To do:We have to find the range of heights of any ten students of our class.Solution :Let the heights of students of your class be 150 cm, 148 cm, 147 cm, 151 cm, 150 cm, 152 cm, 149 cm, 148 cm, 151 cm, 148 cm. The highest height among the ... Read More

Organise the following marks in a class assessment, in a tabular form.
4, 6, 7, 5, 3, 5, 4, 5, 2, 6, 2, 5, 1, 9, 6, 5, 8, 4, 6, 7
$(i)$. Which number is the highest?
$(ii)$. Which number is the lowest?
$(iii)$. What is the range of the data?
$(iv)$. Find the arithmetic mean.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:33:20

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To do:We have to organise the given marks in a class assessment, in a tabular form and answer the given questions.Solution:The given data is as follows, 4, 6, 7, 5, 3, 5, 4, 5, 2, 6, 2, 5, 1, 9, 6, 5, 8, 4, 6, 7Let's tabulate the data as ... Read More

Find the mean of the first five whole numbers.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:33:20

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Given:First five whole numbers.To do:We have to find the mean of the first five whole numbers.Solution:We know that, Mean $=\frac{ \text {Sum of the observations }}{ \text { Number of observations }}$Therefore, The mean of the first five whole numbers $=\frac{0+1+2+3+4}{5}$$=\frac{10}{5}$$=2$Hence, the mean of the first five whole numbers is $2$.  Read More

A cricketer scores the following runs in eight innings:
58, 76, 40, 35, 46, 45, 0, 100.
Find the mean score.

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Tutorialspoint

Updated on 10-Oct-2022 13:33:20

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Given : Scores of cricketer in eight innings are 58, 76, 40, 35, 46, 45, 0, 100.To find :We have to find the mean score.Solution :Score of cricketer in eight innings are 58, 76, 40, 35, 46, 45, 0, 100.Mean $= \frac{ \text { Sum of observations }}{ \text { Number ... Read More

The marks $(out\ of\ 100)$ obtained by a group of students in a science test are 85, 76, 90, 85, 39, 48, 56, 95, 81 and 75. Find the:
$(i)$. Highest and the lowest marks obtained by the students.
$(ii)$. Range of the marks obtained.
$(iii)$. Mean marks obtained by the group.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:33:20

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Given:The marks (out of 100) obtained by a group of students in a science test are 85, 76,  90, 85, 39, 48, 56, 95, 81 and 75.To do:We have to find the:(i) Highest and the lowest marks obtained by the students.(ii) Range of the marks obtained.(iii) Mean marks obtained by ... Read More

The enrolment in a school during six consecutive years was as follows:
1555, 1670, 1750, 2013, 2540, 2820
Find the mean enrolment of the school for this period.

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Tutorialspoint

Updated on 10-Oct-2022 13:33:20

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Given: The enrolment in a school during six consecutive years was as follows:1555, 1670, 1750, 2013, 2540, 2820To do: We have to find the mean enrolment of the school for this period.Solution:Mean calculationMean enrolment $=\frac{ \text { Sum of all observations }}{ \text { Number of observations }}$$=\frac{(1555 + 1670 + ... Read More

The rainfall (in mm) in a city on 7 days of a certain week was recorded as follows:

DayMonTueWedThursFriSatSun
Rainfall (in mm)0.012.22.10.020.55.51.0

$(i)$. Find the range of the rainfall in the above data.
$(ii)$. Find the mean rainfall for the week.
$(iii)$. On how many days was the rainfall less than the mean rainfall."

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:33:20

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Given:The rainfall (in mm) in a city on 7 days of a certain week was recorded.To do:We have to (i) Find the range of the rainfall in the above data.(ii) Find the mean rainfall for the week.(iii) Find on how many days the rainfall was less than the mean rainfall.Solution:(i) Highest ... Read More

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