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About
Simple and Easy Learning
Tutorials Point originated from the idea that there exists a class of readers who respond better to online content and prefer to learn new skills at their own pace from the comforts of their drawing rooms.
The journey commenced with a single tutorial on HTML in 2006 and elated by the response it generated, we worked our way to adding fresh tutorials to our repository which now proudly flaunts a wealth of tutorials and allied articles on topics ranging from programming languages to web designing to academics and much more.
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Tutorialspoint has Published 24147 Articles
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Tutorialspoint
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Steps of construction:Draw a line l, take a point A on it.Take a point P, not on l, and join A to P.Taking A as a center and with a convenient radius draw an arc cutting l at B and AP at C.Taking P as the center and with the ... Read More
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Tutorialspoint
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Follow the steps given below:Draw a line segment YZ of length 5 cm.From Y, we need a point X at a distance of 4.5 cm. So, with Y as the center, draw an arc with a radius of 4.5 cm. From Z, point X is at a distance of 6 ... Read More
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Tutorialspoint
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Given: An equilateral triangle of side $5.5\ cm$.To do: To construct an equilateral triangle of side $5.5\ cm$.Steps of construction: Draw a line segment $BC$ of length $5.5\ cm$.Cut an arc of radius $5\ cm$ from point $B$ and an arc of $5.5\ cm$ from point $C$.Name the point of intersection ... Read More
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Tutorialspoint
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Steps of construction -Draw a line segment QR of length 3.5 cm.From Q, we need a point P is at a distance of 4 cm. So, with Q as the center, draw an arc of radius 4 cm (Now P will be somewhere on this arc. Our job is to ... Read More
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Tutorialspoint
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To do: To construct $∆ABC$ such that $AB=2.5\ cm$, $BC=6\ cm$ and $AC=6.5\ cm$ and measure $\angle B$. Steps of construction -Let us draw a line segment $BC=6\ cm$.Assuming $B$ as the center, let us draw an arc of radius $2.5\ cm$.Assuming point $C$ as the center let us draw ... Read More
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Tutorialspoint
56 Views
To do: To construct $∆DEF$ such that $DE = 5\ cm$, $DF = 3\ cm$ and $\angle EDF = 90^{\circ}$. Steps of construction :Let us draw a line segment $DE=5\ cm$. At the point $D$, let us draw a ray $DX$ making an angle of $90^{\circ}$ with $DE$ such that $\angle ... Read More
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Tutorialspoint
37 Views
To do: To construct an isosceles triangle in which the lengths of each of its equal sides are $6.5\ cm$ and the angle between them is $110^{\circ}$.Steps of construction:Let us draw a line segment $QR=6.5\ cm$. At the point $Q$, let us draw a ray $QX$ making an angle of ... Read More
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Tutorialspoint
63 Views
To do: To construct $∆ABC$ with $BC = 7.5\ cm$, $AC = 5\ cm$ and $m \angle C = 60^{\circ}$.Steps of construction :Let us draw a line segment $BC$ with the length of $7.5\ cm$. From the point $C$, let us draw a ray $CX$ making an angle of $60^{\circ}$ ... Read More
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Tutorialspoint
40 Views
To do: To construct $∆ABC$, given $m\angle A = 60^{\circ}$, $m\angle B = 30^{\circ}$ and $AB = 5.8\ cm$.Steps of construction :Let us draw a line segment $AB=5.8\ cm$. At A, draw ray AY making an angle of $60^{\circ}$ with AB such that $\angle YAB=60^{\circ}$. At $B$, let us draw ... Read More
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Tutorialspoint
37 Views
Given: $EF = 7.2\ cm$, $m\angle E = 110^{\circ}$ and $m\angle F = 80^{\circ}$.To do: To examine whether $∆DEF$ can be constructed.Solution: We know the angle sum property of a triangle which states that the sum of all angles in a triangle is always $180^{\circ}$.So, $\angle E + \angle F + \angle ... Read More