Given:Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. To do:We have to find the total weight of his purchases.Solution:We know that, $1\ kg=1000\ g$Therefore,  Weight of rice purchased $= 5\ kg\ 400\ g$$= (5 + \frac{400}{1000})\ kg$$=(5+0.4)\ kg$$= 5.4\ kg$Weight of ... Read More

To do:We have to subtract the given expressions.Solution:(a) Rs. 18.25 from Rs. 20.75  $20.75$$-18.25$----------- $2.50$-----------Therefore, subtracting Rs. 18.25 from Rs. 20.75, we get Rs. 2.50.(b) 202.54 m from 250 m  $250.00$$-202.54$------------- $47.46$-------------Therefore, subtracting 202.54 m from 250 m, we get $47.46\ m$.(c) Rs. 5.36 from Rs. 8.40  $8.40$$-5.36$----------  $3.04$----------Therefore, subtracting Rs. 5.36 ... Read More

To do:We have to find the value of the given expressions.Solution:(a) $9.756 - 6.28$  $9.756$$-6.280$----------- $3.476$-----------Therefore, $9.756 - 6.28=3.476$(b) $21.05 - 15.27$  $21.05$$-15.27$-------------  $5.78$-------------Therefore, $21.05 - 15.27=5.78$(c) $18.5 - 6.79$  $18.50$ $-6.79$----------  $11.71$----------Therefore, $18.5 - 6.79=11.71$(d) $11.6 - 9.847$  $11.600$$-9.847$-----------  $1.753$-----------Therefore, $11.6 - 9.847=1.753$

Given:Raju bought a book for Rs. 35.65. He gave Rs. 50 to the shopkeeper.To do:We have to find the money he got back from the shopkeeper.Solution:Money given to shopkeeper $= Rs.\ 50.00$Cost of the book $= Rs.\ 35.65$Therefore, The money that Raju will get back from the shopkeeper $=$ Money ... Read More

Given:Rani had Rs. 18.50. She bought one ice cream for Rs. 11.75. To do:We have to find the money she now has.Solution:Money Rani had initially $= Rs.\ 18.50$Cost of the ice cream $= Rs.\ 11.75$Therefore, Money left with Rani $=$ Money Rani had initially $-$ Cost of the ice cream$=Rs.\ 18.50- ... Read More

Given:Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. To do:We have to find the length of the cloth left with her.Solution:We know that, $1\ m=100\ cm$Length of the cloth Tina had $= 20\ m\ 5\ cm$$=(20+\frac{5}{100})\ ... Read More

Given:Namita travels 20 km 50 m every day. Out of this, she travels 10 km 200 m by bus and the rest by auto.To do:We have to find the distance she travels by auto.Solution:We know that, $1\ km=1000\ m$Total distance travelled by Namita $= 20\ km\ 50\ m$$=(20+\frac{50}{1000})\ km$$=(20+0.05)\ km$$= ... Read More

Given:Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes.To do:We have to find the weight of the potatoes.Solution:We know that, $1\ kg=1000\ g$Total weight of vegetables bought by Aakash $= 10\ kg$Weight of ... Read More

To do:We have to find(a) The number of students who obtained marks equal to or more than \( 7 . \)(b) The number of students who obtained marks below 4.Solution:MarksTally MarksNumber of students1||22|||33|||34|||| ||75|||| |66|||| ||77||||58||||49|||3(a) The number of students who obtained marks equal to or more than $7=$ The number of students ... Read More

Given: $AC = 22\ cm, \ BM = 3\ cm, \ DN = 3\ cm$To do: To find the area of the quadrilateral ABCD.Solution:Area of the $∆ ABC = \frac{1}{2}\times base\times height$$=\frac{1}{2}\times AC\times BM$$=\frac{1}{2}\times 22\ cm\times 3\ cm$$=33\ cm^2$Area of the $∆ ADC=\frac{1}{2}\times base\times height$$=\frac{1}{2}\times AC\times DN$$= 1/2\times 22\times 3$$= ... Read More