To do:We have to express the given numbers as meters using decimals.Solution:We know that, $1\ m=100\ cm$This implies, $1\ cm=\frac{1}{100}\ m$Therefore, (a) $15\ cm=15\times\frac{1}{100}\ m$$=\frac{15\times1}{100}\ m$$=0.15\ m$(b) $6\ cm=6\times\frac{1}{100}\ m$$=\frac{6\times1}{100}\ m$$=0.06\ m$(c) $45\ cm=45\times\frac{1}{100}\ m$$=\frac{45\times1}{100}\ m$$=0.45\ m$This implies, $2\ m\ 45\ cm=(2+0.45)\ m$$=2.45\ m$(d) $7\ cm=7\times\frac{1}{100}\ m$$=\frac{7\times1}{100}\ m$$=0.07\ m$This implies, ... Read More

To do:We have to express the given numbers as cm using decimals.Solution:We know that, $1\ cm=10\ mm$This implies, $1\ mm=\frac{1}{10}\ cm$Therefore, (a) $5\ mm=5\times\frac{1}{10}\ cm$$=\frac{5\times1}{10}\ cm$$=\frac{5}{10}\ cm$$=0.5\ cm$(b) $60\ mm=60\times\frac{1}{10}\ cm$$=\frac{60\times1}{10}\ cm$$=\frac{60}{10}\ cm$$=6\ cm$(c) $164\ mm=164\times\frac{1}{10}\ cm$$=\frac{164\times1}{10}\ cm$$=\frac{164}{10}\ cm$$=16.4\ cm$(d) $8\ mm=8\times\frac{1}{10}\ cm$$=\frac{8\times1}{10}\ cm$$=\frac{8}{10}\ cm$$=0.8\ cm$ This implies, $9\ cm\ 8\ ... Read More

To do:We have to express the given numbers as km using decimals.Solution:We know that, $1\ km=1000\ m$This implies, $1\ m=\frac{1}{1000}\ km$Therefore, (a) $8\ m=8\times\frac{1}{1000}\ km$$=\frac{8\times1}{1000}\ km$$=\frac{8}{1000}\ km$$=0.008\ km$(b) $88\ m=88\times\frac{1}{1000}\ km$$=\frac{88\times1}{1000}\ km$$=\frac{88}{1000}\ km$$=0.088\ km$(c) $8888\ m=8888\times\frac{1}{1000}\ km$$=\frac{8888\times1}{1000}\ km$$=\frac{8888}{1000}\ km$$=8.888\ km$(d) $5\ m=5\times\frac{1}{1000}\ km$$=\frac{5\times1}{1000}\ km$$=\frac{5}{1000}\ km$$=0.005\ km$ This implies, $70\ km\ 5\ ... Read More

To do:We have to express the given numbers as kg using decimals.Solution:We know that, $1\ kg=1000\ g$This implies, $1\ g=\frac{1}{1000}\ kg$Therefore, (a) $2\ g=2\times\frac{1}{1000}\ kg$$=\frac{2\times1}{1000}\ kg$$=\frac{2}{1000}\ kg$$=0.002\ kg$(b) $100\ g=100\times\frac{1}{1000}\ kg$$=\frac{100\times1}{1000}\ kg$$=\frac{100}{1000}\ kg$$=0.1\ kg$(c) $3750\ g=3750\times\frac{1}{1000}\ kg$$=\frac{3750\times1}{1000}\ kg$$=\frac{3750}{1000}\ kg$$=3.75\ kg$(d) $8\ g=8\times\frac{1}{1000}\ kg$$=\frac{8\times1}{1000}\ kg$$=\frac{8}{1000}\ kg$$=0.008\ kg$ This implies, $5\ kg\ 8\ ... Read More

To do:We have to find the given sums. Solution:     (a) $0.007$$+8.500 $$+30.080$-------------  $38.587$-------------Therefore, $0.007+8.5+30.08=38.587$. (b) $15.000$$+0.632 $$+13.800$-------------  $29.432$-------------Therefore, $15 + 0.632 + 13.8=29.432$.(c) $27.076$$+0.550 $$+0.004$-------------  $27.630$-------------Therefore, $27.076 + 0.55 + 0.004=27.63$.(d) $25.650$$+9.0 05$$+3.700$-------------  $38.355$-------------Therefore, $25.650 + 9.005 + 3.700=38.355$.(e) $0.750$$+10.425$$+2.000$-------------  $13.175$-------------Therefore, $0.75 + 10.425 + 2=13.175$.(f) $280.69$$+25.20$$+38.00$-------------  $343.89$-------------Therefore, $280.69 + 25.2 + 38=343.89$.

Given:Rashid spent Rs. 35.75 for Maths book and Rs. 32.60 for Science book. To do:We have to find the total amount spent by Rashid.Solution:Money spent on Maths book $= Rs.\ 35.75$Money spent on Science book $= Rs.\ 32.60$Therefore, Total amount spent by Rashid is  $35.75$$+32.60$-----------  $68.35$-----------The total amount of money spent ... Read More

Given:Radhika’s mother gave her Rs. 10.50 and her father gave her Rs. 15.80.To do:We have to find the total amount given to Radhika by the parents.Solution:The amount given by Radhika’s mother $= Rs.\ 10.50$The amount given by Radhika’s father $= Rs.\ 15.80$Therefore, The total amount given to Radhika by her ... Read More

Given:Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser.To do:We have to find the total length of cloth bought by her.Solution:Length of cloth for shirt$=3\ m\ 20\ cm$.Length of cloth for trousers$=2\ m\ 5\ cm$.Therefore, Total length of cloth $=3\ ... Read More

Given:Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening.  To do:We have to find the total distance walked by Naresh.Solution:We know that, $1\ km=1000\ m$Therefore,  The distance walked by Naresh in the morning $= 2\ km\ 35\ m$$= (2 + \frac{35}{1000})\ km$$=(2+0.035)\ ... Read More

Given:Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to reach her school. To do:We have to find the total distance between her school and residence.Solution:We know that, $1\ km=1000\ m$Therefore,  The distance travelled by Sunita by bus ... Read More