Tutorialspoint has Published 24147 Articles

Write the following numbers in the expanded forms:
$(i)$. $2,79,404$
$(ii)$. $30,06,194$
$(iii)$. $28,06,196$
$(iv)$. $1,20,719$
$(v)$. $20,068$

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:38:51

32 Views

Given: $(i)$. $2, 79, 404$$(ii)$. $30, 06, 194$$(iii)$. $28, 06, 196$$(iv)$. $1, 20, 719$$(v)$. $20, 068$To do: To write the above numbers in the expanded forms.Solution:$(i)$. $2, 79, 404$$=200000+70000+9000+400+00+4\times1$$=2\times10000+7\times10000+9\times10000+4\times100+00+4\times1$$=2\times10^5+7\times10^4+9\times10^3+4\times10^2+0\times10^1+4\times10^0$$(ii)$. $30, 06, 194$$=3000000+0+0+6000+100+90+4$$=3\times1000000+0+0+6\times1000+1\times100+9\times10+4\times1$$=3\times10^6+0\times10^5+0\times10^4+6\times10^3+1\times10^2+9\times10^1+4\times10^0$$(iii)$. $28, 06, 196$$=2000000+800000+0+6000+100+90+6$$=2\times1000000+8\times100000+0+6\times1000+1\times100+9\times10+6\times1$$=2\times10^6+8\times10^5+0\times10+6\times10^3+1\times10^2+9\times10^1+6\times10^0$$(iv)$. $1, 20, 719$$=1000000+20000+0+700+10+9$$1\times100000+2\times10000+0+7\times100+10\times1+9\times1$$=1\times10^5+2\times10^4+0+7\times10^2+1\times10^1+9\times10^0$$(v)$. $20, 068$$=20000+00+00+60+8$$=2\times10000+0\times1000+0\times100+6\times10+8\times1$$=2\times10^4+0\times10^3+0\times10^2+6\times10^1+8\times10^0$Read More

Find the number from each of the following expanded forms:
$(a)$. $8\\times10^4+6\\times10^3+0\\times10^2+4\\times10^1+5\\times10^0$
$(b)$. $4\\times10^4+5\\times10^3+3\\times10^2+2\\times10^0$
$(c)$. $3\\times10^4+7\\times10^2+5\\times10^0$
$(d)$. $9\\times10^5+2\\times10^2+3\\times10^1$

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:38:51

44 Views

Given:$(a)$. $8\times10^4+6\times10^3+0\times10^2+4\times10^1+5\times10^0$$(b)$. $4\times10^5+5\times10^3+3\times10^2+2\times10^0$$(c)$. $3\times10^4+7\times10^2+5\times10^0$$(d)$. $9\times10^5+2\times10^2+3\times10^1$To do: To find the number from each of the following expanded forms.Solution: $(a)$. $8\times10^4+6\times10^3+0\times10^2+4\times10^1+5\times10^0$ $=8\times10000+6\times1000+0\times100+4\times10+5\times1$$=80000+6000+0+40+5$$=86, 045$$(b)$. $4\times10^5+5\times10^3+3\times10^2+2\times10^0$ $=4\times100000+5\times1000+3\times100+2\times1$$=400000+5000+300+2$$=405302$$(c)$. $3\times10^4+7\times10^2+5\times10^0$$=3\times10000+7\times100+5\times1$$=30000+700+5$$=30705$$(d)$. $9\times10^5+2\times10^2+3\times10^1$ $=9\times100000+2\times100+3\times10$$=900230$Read More

Express the following numbers in standard form:
$(i)$. $5,00,00,000$
$(ii)$. $70,00,000$
$(iii)$. $3,18,65,00,000$
$(iv)$. $3,90,878$
$(v)$. $39087.8$
$(vi)$ $3908.78$

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:38:51

49 Views

Given: $(i)$. $5,00,00,000$ $(ii)$. $70,00,000$ $(iii)$. $3,18,65,00,000$$(iv)$. $3,90,878$ $(v)$. $39087.8$ $(vi)$ $3908.78$To do: To express the above numbers in standard form.Solution: $(i)$. $5,00,00,000$$=5\times10000000$$=5\times10^7$$(ii)$. $70,00,000$$=7\times1000000$$=7\times10^6$$(iii)$. $3,18,65,00,000$$=3.1865\times 10^9$$(iv)$. $3,90,878$$=3.90878\times10^5$$(v)$. $39087.8$$=390878\times 10^4$$(vi)$ $3908.78$$=3.90878\times 1000$$=3.90878\times 10^3$

If the length and breadth of a rectangle are \\( 10 \\mathrm{~cm} \\) and \\( 20 \\mathrm{~cm} \\), respectively, find the length of its diagonal.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:38:51

247 Views

Given:The length and breadth of a rectangle are \( 10 \mathrm{~cm} \) and \( 20 \mathrm{~cm} \).To do:We have to find the length of its diagonal.Solution:We know that, Length of the diagonal of a rectangle of length $l$ and breadth $b$ is $\sqrt{l^2+b^2}$The length of the rectangle $=10\ cm$The breadth ... Read More

Find out the square root of the below numbers by using the division method
(1) 529
(2) 1369
(3) 363609
(4) 900

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:38:51

52 Views

To do:We have to find the square root of the given numbers using the division method.Solution:(i) Square root of 529 is, 232529443129129   0Therefore, The square root of 529 is 23.(ii) Square root of 1369 is, 3731369 967  469  469   0Therefore, The square root of 1369 is 37.(iii) Square root of 363609 ... Read More

What are common factors and common multiples?

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:38:51

57 Views

Common Factor:A common factor is a whole number which is a factor of two or more numbers. Common Multiples:The multiples which are shared by a given set of numbers are called common multiples.For example:Factors of 10 are 1, 2, 5, 10Factors of 20 are 1, 2, 4, 5, 10, 20Common factors ... Read More

The following figures have more than one line of symmetry. Such figures are said to have multiple lines of symmetry.

Identify multiple lines of symmetry

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:38:51

48 Views

Given: Some figures have more than one line of symmetry as shown in the given figures. Such figures are said to have multiple lines of symmetry.To do: To identify multiple lines of symmetry, if any, in each of the given figures.Solution: In order to check the symmetry and find their lines ... Read More

Visualise \\( 4 . \\overline{26} \\) on the number line, up to 4 decimal places.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:38:48

84 Views

Given:Given number is $4 . \overline{26}$.To do:We have to visualise the representation of $4 . \overline{26}$ on the number line using successive magnification.Solution:$4 . \overline{26}$ up to 4 decimal places is 4.2626.Therefore, $4.2626$ lies between 4 and 5.So, we divide the number line into 10 equal parts and mark each ... Read More

Express \\( 0.99999 \\ldots \\) in the form \\( \\frac{p}{q} \\). Are you surprised by your answer? With your teacher and classmates discuss why the answer makes sense.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:38:47

48 Views

Given:A number $0.99999\ ....$To do:We have to express $0.99999\ ....$ in the form $\frac{p}{q}$.Solution:Let $x=0.99999.....$_________(i)Multiplying equation (i) by $10$, we get, $10x=9.9999.....$_______(ii)Subtract (i) from (ii), we get, $10x-x=9.9999.......-0.9999.........$$\Rightarrow 9x=9$$\Rightarrow x=\frac{9}{9}=1$Here, $p=1$ and $q=1$Therefore, $0.9999....=1$The difference between 1 and 0.999999 is 0.000001 which is negligible.Hence, we can conclude that 0.999 is ... Read More

Advertisements