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In Fig. 6.42, if lines \\( \\mathrm{PQ} \\) and \\( \\mathrm{RS} \\) intersect at point \\( \\mathrm{T} \\), such that \\( \\angle \\mathrm{PRT}=40^{\\circ}, \\angle \\mathrm{RPT}=95^{\\circ} \\) and \\( \\angle \\mathrm{TSQ}=75^{\\circ} \\), find \\( \\angle \\mathrm{SQT} \\).
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:46

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Given:Lines $PQ$ and $RS$ intersect at point $T$, such that $\angle PRT=40^o, \angle RPT=95^o$ and $\angle TSQ=75^o$.To do:We have find $\angle SQT$.Solution:Let us consider $\triangle PRT$.We know that, The sum of the interior angles of a triangle is always $180^o$.Therefore, $\angle PRT+\angle RPT+\angle PTR=180^o$By substituting the values of $\angle PRT$ ... Read More

In Fig. \\( 6.40, \\angle \\mathrm{X}=62^{\\circ}, \\angle \\mathrm{XYZ}=54^{\\circ} \\). If \\( \\mathrm{YO} \\) and \\( Z \\mathrm{O} \\) are the bisectors of \\( \\angle \\mathrm{XYZ} \\) and \\( \\angle \\mathrm{XZY} \\) respectively of \\( \\triangle \\mathrm{XYZ} \\) find \\( \\angle \\mathrm{OZY} \\) and \\( \\angle \\mathrm{YOZ} \\).
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:44

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Given:$\angle X=62^o$, \angle XYZ=54^o$.$YO$ and $ZO$ are bisectors of $\angle XYZ$ and $\angle XZY$ respectively of $\triangle XYZ$.To do:We have to find $\angle OZY$ and $\angle YOZ$.Solution:We know that the sum of the interior angles of the triangle are always $180^o$.This implies, $\angle X+\angle XYZ+\angle XZY=180^o$By substituting the values of ... Read More

In Fig. 6.39, sides \\( \\mathrm{QP} \\) and \\( \\mathrm{RQ} \\) of \\( \\triangle \\mathrm{PQR} \\) are produced to points \\( \\mathrm{S} \\) and T respectively. If \\( \\angle \\mathrm{SPR}=135^{\\circ} \\) and \\( \\angle \\mathrm{PQT}=110^{\\circ} \\), find \\( \\angle \\mathrm{PRQ} \\).
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:43

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Given:Sides $QP$ and $RQ$ of $\triangle PQR$ are produced to points $S$ and $T$ respectively.$\angle SPR=135^o$ and $\angle PQT=110^o$.To do:We have to find $\angle PRQ$.Solution:We know that, The sum of the measures of the angles in linear pairs is always $180^o$.This implies, $\angle TQP+\angle PQR=180^O$By substituting the value of $\angle ... Read More

In which quadrant or on which axis do each of the points \\( (-2,4),(3,-1),(-1,0) \\), \\( (1,2) \\) and \\( (-3,-5) \\) lie? Verify your answer by locating them on the Cartesian plane.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:41

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To do:We have to find in which quadrant or on which axis the points \( (-2, 4), (3, -1), (-1, 0) \), \( (1, 2) \) and \( (-3, -5) \) lie.Solution: To find the quadrant or axis of the points $(-2, 4), (3, -1), (-1, 0), (1, 2)$ and $(-3, ... Read More

See below figure, and write the following:

(i) The coordinates of $B$.
(ii) The coordinates of $C$.
(iii) The point identified by the coordinates $(-3

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:40

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To do:We have to find(i) The coordinates of $B$.(ii) The coordinates of $C$.(iii) The point identified by the coordinates $(-3, -5)$.(iv) The point identified by the coordinates $(2, -4)$.(v) The abscissa of the point $D$.(vi) The ordinate of the point $H$.(vii) The coordinates of the point $L$.(viii) The coordinates of ... Read More

Write the answer of each of the following questions:
(i) What is the name of horizontal and the vertical lines drawn to determine the
position of any point in the Cartesian plane?
(ii) What is the name of each part of the plane formed by these two lines?
(iii) Write the name of the point where these two lines intersect.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:37

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To do:We have to answer the given questions.Solution: (i) The horizontal line that is drawn to determine the position of any point in the Cartesian plane is called the X-axis. The vertical line that is drawn to determine the position of any point in the Cartesian plane is called the Y-axis.(ii) The ... Read More

In Fig. 6.32, if \\( \\mathrm{AB} \\| \\mathrm{CD}, \\angle \\mathrm{APQ}=50^{\\circ} \\) and \\( \\angle \\mathrm{PRD}=127^{\\circ} \\), find \\( x \\) and \\( y \\).
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:35

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Given:$AB \parallel CD$, $\angle APQ=150^0$ and $\angle PRD=127^o$.To do:We have to find $x$ and $y$.Solution:We know that, If the lines intersected by the transversal are parallel, alternate interior angles are equal.This implies, $\angle APQ=\angle PQR$By substituting the values we get, $\angle APQ=\angle PRD$This implies, $x=50^o$In the similar way, we get, ... Read More

In Fig. 6.31, if \\( \\mathrm{PQ} \\| \\mathrm{ST}, \\angle \\mathrm{PQR}=110^{\\circ} \\) and \\( \\angle \\mathrm{RST}=130^{\\circ} \\), find \\( \\angle \\mathrm{QRS} \\).
[Hint : Draw a line parallel to ST through point R.]
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:33

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Given:$PQ \parallel ST$, $\angle PQR=130^o$.To do:We have to find $\angle QRS$.Solution:Let us draw a line parallel to $ST$ through the point $R$ and name it $UV$.We know that, The angles on the same side of the transversal are equal to $180^o$.Therefore, $\angle RST+\angle SRV=180^o$This implies, $\angle SRV=180^o-130^o$  (Since, $\angle S=130^o$)We ... Read More

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