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In \( \triangle \mathrm{ABC} \) and \( \triangle \mathrm{DEF}, \mathrm{AB}=\mathrm{DE}, \mathrm{AB} \| \mathrm{DE}, \mathrm{BC}=\mathrm{EF} \) and \( \mathrm{BC} \| EF \). Vertices \( \mathrm{A}, \mathrm{B} \) and \( \mathrm{C} \) are joined to vertices D, E and F respectively (see below figure).

Show that
(i) quadrilateral ABED is a parallelogram
(ii) quadrilateral \( \mathrm{BEFC} \) is a parallelogram
(iii) \( \mathrm{AD} \| \mathrm{CF} \) and \( \mathrm{AD}=\mathrm{CF} \)
(iv) quadrilateral ACFD is a parallelogram
(v) \( \mathrm{AC}=\mathrm{DF} \)
(vi) \( \triangle \mathrm{ABC} \equiv \triangle \mathrm{DEF} \)."

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:02

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Given:In \( \triangle \mathrm{ABC} \) and \( \triangle \mathrm{DEF}, \mathrm{AB}=\mathrm{DE}, \mathrm{AB} \| \mathrm{DE}, \mathrm{BC}=\mathrm{EF} \) and \( \mathrm{BC} \| EF \).To do :We have to show that(i) quadrilateral ABED is a parallelogram(ii) quadrilateral \( \mathrm{BEFC} \) is a parallelogram(iii) \( \mathrm{AD} \| \mathrm{CF} \) and \( \mathrm{AD}=\mathrm{CF} \)(iv) quadrilateral ACFD ... Read More

\\( \\mathrm{ABCD} \\) is a rectangle in which diagonal \\( \\mathrm{AC} \\) bisects \\( \\angle \\mathrm{A} \\) as well as \\( \\angle \\mathrm{C} \\). Show that:
(i) \\( \\mathrm{ABCD} \\) is a square
(ii) diagonal \\( \\mathrm{BD} \\) bisects \\( \\angle \\mathrm{B} \\) as well as \\( \\angle \\mathrm{D} \\).

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:01

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Given:$ABCD$ is a rectangle in which diagonal $AC$ bisects $\angle A$ as well as $\angle C$.To do :We have to show that(i) $ABCD$ is a square(ii) Diagonal $BD$ bisects $\angle B$ as well as $\angle D$. Solution :(i) A square is a rectangle when all sides are equal. In the above figure, ... Read More

In parallelogram \\( \\mathrm{ABCD} \\), two points \\( \\mathrm{P} \\) and \\( \\mathrm{Q} \\) are taken on diagonal \\( \\mathrm{BD} \\) such that \\( \\mathrm{DP}=\\mathrm{BQ} \\) (see below figure). Show that:
(i) \\( \\triangle \\mathrm{APD} \\equiv \\triangle \\mathrm{CQB} \\)
(ii) \\( \\mathrm{AP}=\\mathrm{CQ} \\)
(iii) \\( \\triangle \\mathrm{AQB} \\equiv \\triangle \\mathrm{CPD} \\)
(iv) \\( \\mathrm{AQ}=\\mathrm{CP} \\)
(v) \\( \\mathrm{APCQ} \\) is a parallelogram
"

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:01

29 Views

Given:In parallelogram \( \mathrm{ABCD} \), two points \( \mathrm{P} \) and \( \mathrm{Q} \) are taken on diagonal \( \mathrm{BD} \) such that \( \mathrm{DP}=\mathrm{BQ} \)To do :We have to show that (i) \( \triangle \mathrm{APD} \equiv \triangle \mathrm{CQB} \)(ii) \( \mathrm{AP}=\mathrm{CQ} \)(iii) \( \triangle \mathrm{AQB} \equiv \triangle \mathrm{CPD} \)(iv) ... Read More

\\( \\mathrm{ABCD} \\) is a rhombus. Show that diagonal \\( \\mathrm{AC} \\) bisects \\( \\angle \\mathrm{A} \\) as well as \\( \\angle \\mathrm{C} \\) and diagonal \\( \\mathrm{BD} \\) bisects \\( \\angle \\mathrm{B} \\) as well as \\( \\angle \\mathrm{D} \\).

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:59

57 Views

Given:\( \mathrm{ABCD} \) is a rhombus.To do :We have to show that diagonal \( \mathrm{AC} \) bisects \( \angle \mathrm{A} \) as well as \( \angle \mathrm{C} \) and diagonal \( \mathrm{BD} \) bisects \( \angle \mathrm{B} \) as well as \( \angle \mathrm{D} \).Solution :  $AC$ and $BD$ are the ... Read More

The mass of object A is 6kg whereas that of another object B is 34 kg. Which of the two objects A or B has more inertia?

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:58

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Given:The mass of object A is 6kg whereas that of another object B is 34 kg. To do:We have to find the object that has more inertia.Solution:We know that, Inertia is directly proportional to the mass of the body. The more the mass, the more inertia.Here, object B which is 34 kg is ... Read More

Show that if the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:58

51 Views

Given :Diagonals of the quadrilateral bisect each other at right angles.To do :We have to show that it is a rhombus.Solution:                              Let $ABCD$ be a quadrilateral in which diagonals bisect each other at right angles.So, $OA=OC, OB=OD$$\angle ... Read More

Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:58

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Given :Diagonals of the quadrilateral are equal and bisect each other at right angles.To do :We have to show that it is square.Solution :                              Let $ABCD$ be a quadrilateral in which diagonals are equal and bisect each ... Read More

In an isosceles triangle \\( \\mathrm{ABC} \\), with \\( \\mathrm{AB}=\\mathrm{AC} \\), the bisectors of \\( \\angle \\mathrm{B} \\) and \\( \\angle \\mathrm{C} \\) intersect each other at \\( O \\). Join \\( A \\) to \\( O \\). Show that :
(i) \\( \\mathrm{OB}=\\mathrm{OC} \\)
(ii) \\( \\mathrm{AO} \\) bisects \\( \\angle \\mathrm{A} \\)

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:57

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Given:In an isosceles triangle  $ABC$, with $AB=A$, the bisectors of $\angle B$ and $\angle C$ intersect each other at $O$. Join $A$ to $O$.To do:We have to show that(i) $OB=OC$(ii) $AO$ bisects $\angle A$.Solution:(i) We know that, In an isosceles triangle all the angle are equal.This implies, $\angle B= \angle ... Read More

In \\( \\triangle \\mathrm{ABC}, \\mathrm{AD} \\) is the perpendicular bisector of \\( \\mathrm{BC} \\) (see Fig. 7.30). Show that \\( \\triangle \\mathrm{ABC} \\) is an isosceles triangle in which \\( \\mathrm{AB}=\\mathrm{AC} \\).
"

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:40:57

52 Views

Given:In $\triangle ABC, AD$ is the perpendicular bisector of $BC$.To do:We have to show that $\triangle ABC$ is an isosceles triangle in which  $AB=AC$.Solution:Let us consider $\triangle ADB$ and$\triangle ADC$, We know that, According to Rule of Side-Angle-Side Congruence:Triangles are said to be congruent if any pair of corresponding sides ... Read More

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