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In figure below, \\( \\mathrm{ABCD} \\) is a parallelogram, \\( \\mathrm{AE} \\perp \\mathrm{DC} \\) and \\( \\mathrm{CF} \\perp \\mathrm{AD} \\). If \\( \\mathrm{AB}=16 \\mathrm{~cm}, \\mathrm{AE}=8 \\mathrm{~cm} \\) and \\( \\mathrm{CF}=10 \\mathrm{~cm} \\), find \\( \\mathrm{AD} \\).
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:35

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Given:$ABCD$ is a parallelogram, $AE \perp DC$ and $CF \perp AD$.$AB = 16\ cm, AE = 8\ cm$ and $CF = 10\ cm$.To do:We have to find $AD$.Solution:We know that, Area of a parallelogram $=$ Base $\times$ AltitudeTherefore, Area of parallelogram $ABCD = AB \times AE$$= 16 \times 8$$= 128\ ... Read More

Which of the following figures lie on the same base and between the same parallels. In such a case, write the common base and the two parallels.
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:34

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To do:We have to find whether the given figures lie on the same base and between the same parallels and write the common base and two parallels.Solution:(i) From the figure, Trapezium $ABCD$ and triangle $DPC$ on the same base $DC$ and between the same parallels $AB$ and $DC$ . (ii) From ... Read More

Complete the hexagonal and star shaped Rangolies [see Fig. \\( 7.53 \\) (i) and (ii)] by filling them with as many equilateral triangles of side \\( 1 \\mathrm{~cm} \\) as you can. Count the number of triangles in each case. Which has more triangles?
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:33

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Given:hexagonal and star shaped rangolies.To do:We have to fill the given rangolies with as many equilateral triangles of side $1\ cm$ as we can and count the number of triangles in each case, which has more triangles.Solution:Let us calculate the area of hexagon and star, Area of hexagon$= 6\times\frac{25\sqrt 3}{4}$Area ... Read More

In a huge park, people are concentrated at three points (see Fig. 7.52):
A: where there are different slides and swings for children,
B: near which a man-made lake is situated,
\\( C \\) : which is near to a large parking and exit.
Where should an icecream parlour be set up so that maximum number of persons can approach it?
(Himt : The parlour should be equidistant from \\( \\mathrm{A}, \\mathrm{B} \\) and \\( \\mathrm{C} \\) )
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:31

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Given:In a huge park, people are concentrated at three points.To do:We have to find where to set up an icecream parlour so that maximum number of persons can approach.Solution:Let us consider $ABC$ as a triangle.Such that the three points in a triangle will be equidistant at circumcentre from the points ... Read More

In a triangle locate a point in its interior which is equidistant from all the sides of the triangle.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:30

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To do:In a triangle locate a point in its interior which is equidistant from all the sides of the triangle.Solution:Let us consider a $\triangle ABC$We know that, A point in the interior of the triangle, equidistant from all the sides of the triangle will be its Incenter.The incenter of a ... Read More

\\( \\mathrm{ABC} \\) is a triangle. Locate a point in the interior of \\( \\triangle \\mathrm{ABC} \\) which is equidistant from all the vertices of \\( \\triangle \\mathrm{ABC} \\).

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:27

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Given: $ABC$ is a triangle.To do:We have to locate a point in the interior of $\triangle ABC$ which is equidistant from all the vertices of $\triangle ABC$.Solution:Let us consider a $\triangle ABC$We know that, A point in the interior of the triangle which is equidistant from all the vertices is called ... Read More

Show that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.

Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:26

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To do:We have to show that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.Solution:Let us draw a line $l$ and mark a point $P$ on it.Now let us draw a perpendicular line $AB$ on $l$ and let us point ... Read More

In Fig 7.51, PR \\( > \\) PQ and \\( \\mathrm{PS} \\) bisects \\( \\angle \\mathrm{QPR} \\). Prove that \\( \\angle \\mathrm{PSR}>\\angle \\mathrm{PSQ} \\).
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:24

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Given:$PR > PQ$ and $PS$ bisects $\angle QPR$.To do:We have to prove that $\angle PSR > \angle PSQ$.Solution:Let us consider $\triangle PQR$We have, $PR > PQ$We know that, The angle opposite the longer side will always be larger.This implies, $\angle PQR > \angle PRQ$...(i)Since we have, $PS$ bisects $\angle QPR$We ... Read More

\\( \\mathrm{AB} \\) and \\( \\mathrm{CD} \\) are respectively the smallest and longest sides of a quadrilateral \\( \\mathrm{ABCD} \\) (see Fig. 7.50). Show that \\( \\angle A>\\angle C \\) and \\( \\angle \\mathrm{B}>\\angle \\mathrm{D} \\).
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Tutorialspoint

Tutorialspoint

Updated on 10-Oct-2022 13:41:23

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Given:$AB$ and $CD$ are respectively the smallest and longest sides of a quadrilateral $ABCD$.To do:We have to show that $\angle A>\angle C$ and $\angle B>\angle $D$.Solution:Let us consider $\triangle ABD$, We have, $AB We know that, The angle opposite the longer side will always be larger.This implies, $\angle ADB In ... Read More

In Fig. 7.49, \\( \\angle \\mathrm{B}"

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Tutorialspoint

Updated on 10-Oct-2022 13:41:21

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Given:$\angle B

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