Arnab Chakraborty

Arnab Chakraborty

3,768 Articles Published

Articles by Arnab Chakraborty

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Program to find minimum difference of max and mins after updating elements at most three times in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 241 Views

Suppose we have a list of numbers called nums, now consider an operation where we can update an element to any value. We can perform at most 3 of such operations, we have to find the resulting minimum difference between the max and the min value in nums.So, if the input is like nums = [2, 3, 4, 5, 6, 7], then the output will be 2, as we can change the list to [4, 3, 4, 5, 4, 4] and then 5 - 3 = 2.To solve this, we will follow these steps −if size of nums

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People Whose List of Favorite Companies Is Not a Subset of Another List in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 181 Views

Suppose we have an array called favorite companies where favoriteCompanies[i] is the list of favorites companies of the ith person. We have to find the indices of people whose list of favorite companies is not a subset of any other list of favorites companies.So, if the input is like favoriteCompanies = [["TCS", "google", "facebook"], ["google", "microsoft"], ["google", "facebook"], ["google"], ["amazon"]], then the output will be [0, 1, 4], this is because person with index=2 has ["google", "facebook"] which is a subset of favoriteCompanies[0]= ["TCS", "google", "facebook"] corresponding to the person with index 0.Now person with index=3 has ["google"] which is ...

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Program to find number of sublists whose sum is given target in python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 569 Views

Suppose we have a list of numbers called nums and another value target, we have to find the number of sublists whose sum is same as target.So, if the input is like nums = [3, 0, 3] target = 3, then the output will be 4, as we have these sublists whose sum is 3: [3], [3, 0], [0, 3], [3].To solve this, we will follow these steps:temp := an empty maptemp[0] := 1s := 0ans := 0for i in range 0 to size of nums, dos := s + nums[i]comp := s - targetif comp is in temp, thenans ...

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Program to find maximum time to finish K tasks in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 412 Views

Suppose we have a matrix of tasks where each row has 3 values. We also have another value k. We have to select k rows from tasks, call it S, such that the following sum is minimized and return the sum as: maximum of (S[0, 0], S[1, 0], ...S[k - 1, 0]) + maximum of (S[0, 1], S[1, 1], ...S[k - 1, 1]) + maximum of (S[0, 2], S[1, 2], ...S[k - 1, 2]) We can also say like: Each of the 3 columns contribute to a cost, and is calculated by taking the max value of that column in ...

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Maximum Number of Vowels in a Substring of Given Length in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 634 Views

Suppose we have a string s and an integer k. We have to find the maximum number of vowel letters in any substring of s with length k.So, if the input is like s = "abciiidef", k = 3, then the output will be 3To solve this, we will follow these steps −cnt := 0Define one set mfor each vowel v, doinsert v into mret := 0for initialize i := 0, when i < k, update (increase i by 1), do −cnt := cnt + (1 when s[i] is in m, otherwise 0)ret := maximum of ret and cntn := ...

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Program to count non-empty subsets where sum of min and max element of set is less than k in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 287 Views

Suppose we have a list of numbers called nums and another value k, we have to find the number of non-empty subsets S such that min of S + max of S K, doj := j - 1if i

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Pseudo-Palindromic Paths in a Binary Tree in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 378 Views

Suppose we have a binary tree where node values are digits from 1 to 9. One path in the binary tree is said to be pseudo-palindromic when at least one permutation of the node values in the path is a palindrome. We have to find the number of pseudo-palindromic paths going from the root node to leaf nodes.So, if the input is likethen the output will be 2, this is because there are three paths going from the root node to leaf nodes − red path follows [2, 3, 3], the green path follows [2, 1, 1], and the path ...

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Program to find most frequent subtree sum of a binary tree in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 248 Views

Suppose we have a binary tree, we have to find the most frequent subtree sum. The subtree sum of a node is actually the sum of all values under a node, including the node itself.So, if the input is likethen the output will be 3 as it occurs twice − once as the left leaf, and once as the sum of 3 - 6 + 6.To solve this, we will follow these steps −count := an empty mapDefine a function getSum() . This will take nodeif node is null, thenreturn 0mySum := getSum(left of node) + getSum(right of node) + ...

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Program to find minimum possible maximum value after k operations in python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 1K+ Views

Suppose we have a list of numbers called nums and another value k. Now let us consider an operation where we can subtract 1 from any element in the list. We can perform this operation k times. We have to find the minimum possible maximum value in the list after k such operations.So, if the input is like nums = [3, 4, 6, 5] k = 6, then the output will be 3, as we can decrease 4 once, 6 thrice and 5 twice to get [3, 3, 3, 3].To solve this, we will follow these steps:sort numbers in reverse ...

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Program to check whether every one has at least a friend or not in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 394 Views

Suppose we have n people represented as a number from 0 to n - 1, we also have a list of friend’s tuples, where friends[i][0] and friends[i][1] are friends. We have to check whether everyone has at least one friend or not.So, if the input is like n = 3 friends = [ [0, 1], [1, 2] ], then the output will be True, as Person 0 is friends of Person 1, Person 1 is friends of Person 0 and 2, and Person 2 is friends of Person 1.To solve this, we will follow these steps −people := a list ...

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