Arnab Chakraborty

Arnab Chakraborty

3,768 Articles Published

Articles by Arnab Chakraborty

Page 196 of 377

Duplicate Zeros in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 1K+ Views

Suppose we have a fixed length array of integers, we have to duplicate each occurrence of zero, shifting the remaining elements to the right side.Note that elements beyond the length of the original array are not written.So suppose the array is like [1, 0, 2, 3, 0, 4, 5, 0], then after modification it will be [1, 0, 0, 2, 3, 0, 0, 4]To solve this, we will follow these steps −copy arr into another array arr2, set i and j as 0while i < size of arr −if arr2[i] is zero, thenarr[i] := 0increase i by 1if i < ...

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Distribute Candies to People in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 2K+ Views

Suppose we want to distribute some number of candies to a row of n people in the following way −We then give 1 candy to the first people, 2 candies to the second people, and so on until we give n candies to the last people.After that, we go back to the start of the row again, give n + 1 candies to the first people, n + 2 candies to the second people, and so on until we give 2 * n candies to the last people.We will repeat this process until we run out of candies. The last ...

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Find the count of numbers that can be formed using digits 3 and 4 only and having length at max N in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 133 Views

Given a number N. We have to find the count of such numbers that can be formed using digit 3 and 4. So if N = 6, then the numbers will be 3, 4, 33, 34, 43, 44.We can solve this problem if we look closely, for single digit number it has 2 numbers 3 and 4, for digit 2, it has 4 numbers 33, 34, 43, 44. So for m digit numbers, it will have 2m values.Example#include #include using namespace std; long long countNumbers(int n) {    return (long long)(pow(2, n + 1)) - 2; } int main() {    int n = 3;    cout

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Defanging an IP Address in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 1K+ Views

Suppose we have a valid IPv4 IP address. We have to return the Defanged version of the IP address. A Defanged IP address is basically replace every period “.” by “[.]” So if the IP address is “192.168.4.1”, the output will be “192[.]168[.]4[.]1”To solve this, we will follow these steps −We will split the string using dot, then put each element separated by “[.]”ExampleLet us see the following implementation to get better understanding −class Solution(object):    def defangIPaddr(self, address):       address = address.split(".")       return "[.]".join(address) ob1 = Solution() print(ob1.defangIPaddr("192.168.4.1"))Input"192.168.4.1"Output"192[.]168[.]4[.]1"

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Relative Sort Array in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 837 Views

Suppose we have two arrays arr1 and arr2, the elements of arr2 are unique, and all elements in arr2 are also present in arr1. We have to sort the elements of arr1 in such a way that the relative ordering of items in arr1 are the same as in arr2. If there are some elements that are not present in arr2, they should be placed at the end of arr1 in ascending order. So if the arr1 is like [2, 3, 1, 3, 2, 4, 6, 7, 9, 2, 19], and arr2 is like [2, 1, 4, 3, 9, 6], ...

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Find the count of Strictly decreasing Subarrays in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 273 Views

Suppose we have an array A. And we have to find the total number of strictly decreasing subarrays of length > 1. So if A = [100, 3, 1, 15]. So decreasing sequences are [100, 3], [100, 3, 1], [15] So output will be 3. as three subarrays are found.The idea is find subarray of len l and adds l(l – 1)/2 to result.Example#include using namespace std; int countSubarrays(int array[], int n) {    int count = 0;    int l = 1;    for (int i = 0; i < n - 1; ++i) {       if ...

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Find the compatibility difference between two arrays in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 591 Views

Consider there are two friends and now they want to test their bonding. So they will check, how much compatible they are. Given the numbers n, numbered from 1..n. And they are asked to rank the numbers. They have to find the compatibility difference between them. The compatibility difference is basically the number of mismatches in the relative ranking of the same movie given by them. So if A = [3, 1, 2, 4, 5], and B = [3, 2, 4, 1, 5], then the output will be 2. The compatibility difference is 2, as first ranks movie 1 before ...

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Find the count of substrings in alphabetic order in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 187 Views

Suppose we have a string of length n. It contains only uppercase letters. We have to find the number of substrings whose character is occurring in alphabetical order. Minimum size of the substring will be 2. So if the string is like: “REFJHLMNBV”, and substring count is 2, they are “EF” and “MN”.So to solve this, we will follow these steps −Check whether str[i] + 1 is same as the str[i+1], if so, then increase the result by 1, and iterate the string till next character which is out of alphabetic order, otherwise continue.Example#include using namespace std; int countSubstr(string main_str) ...

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Day of the Year in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 4K+ Views

Suppose, we have a date in the format “YYYY-MM-DD”. We have to return the day number of the year. So if the date is “2019-02-10”, then this is 41st day of the year.To solve this, we will follow these steps −Suppose D is an array of day count like [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]Convert the date into list of year, month and dayif the year is leap year then set date D[2] = 29Add up the day count up to the month mm – 1. and day count after that.ExampleLet us see ...

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Prime Arrangements in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 362 Views

We have to find the number of permutations of 1 to n, so the prime numbers are placed at prime indices. The answers may be large, return the answer modulo 10^9 + 7. So if n = 5, then output will be 12. So there will be 12 permutations. one possible permutation will be [1, 2, 5, 4, 3], one invalid permutation is [5, 2, 3, 4, 1] because 5 is placed at index 1, that is not prime.To solve this, we will follow these steps −Define one method called getNum, as follows −prime := list of all primes from ...

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