Arnab Chakraborty

Arnab Chakraborty

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Articles by Arnab Chakraborty

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Find the last digit when factorial of A divides factorial of B in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 209 Views

If we have two integers A and B, and B >= A, we have to compute the last digit of the B! / A! When the value of A = 2 and B = 4, then result is 2, 2! = 2 and 4! = 24, so 24/2 = 12. the last digit is 2.As we know that the last digit of factorial will be in set {0, 1, 2, 4, 6}, then follow these steps to solve this problem −We will find the difference between A and Bif diff >=5, then answer is 0otherwise, iterate from (A + 1) ...

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Convert Binary Number in a Linked List to Integer in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 897 Views

Suppose we have one ‘head’ which is a reference node to a singly-linked list. The value of each node present in the linked list is either 0 or 1. This linked list stores the binary representation of a number. We have to return the decimal value of the number present in the linked list. So if the list is like [1, 0, 1, 1, 0, 1]To solve this, we will follow these steps −x := convert the list elements into an arraythen reverse the list xans := 0, and temp := 1for i in range i := 0, to size ...

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Decrypt String from Alphabet to Integer Mapping in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 874 Views

Suppose we have a string s that is formed by digits ('0' - '9') and '#'. We have to map s to one English lowercase characters as follows −Characters ('a' to 'i') are represented by ('1' to '9') respectively.Characters ('j' to 'z') are represented by ('10#' to '26#') respectively.We have to find the string formed after mapping. We are taking one assumption that a unique mapping will always exist. So if the input is like “10#11#12”, then it will be “jkab”. As 10# is j, 11# is k, 1 is a and 2 is b.To solve this, we will follow ...

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Find smallest values of x and y such that ax – by = 0 in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 188 Views

Suppose we have two values a and b. We have to find x and y, such that ax – by = 0. So if a = 25 and b = 35, then x = 7 and y = 5.To solve this, we have to calculate the LCM of a and b. LCM of a and b will be the smallest value that can make both sides equal. The LCM can be found using GCD of numbers using this formula −LCM (a,b)=(a*b)/GCD(a,b)Example#include #include using namespace std; void getSmallestXY(int a, int b) {    int lcm = (a * b) / __gcd(a, b);    cout

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Height Checker in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 1K+ Views

Suppose a set of students have to be arranged in non-decreasing order of their heights for a photograph. If we have an array of students, we have to return the minimum number of students that are not present in correct position. So if the array is like [1, 1, 4, 2, 1, 3], then output will be 3. So students with height 4, 3 and the last 1 are not standing in the correct position.To solve this, we will follow these steps −answer := 0let x := Array in sorted formley y := Arrayfor i := 0 to size of ...

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Find sum of a number and its maximum prime factor in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 225 Views

Suppose we have a positive number n, and we have to find the sum of N and its maximum prime factor. So when the number is 26, then maximum prime factor is 13, so sum will be 26 + 13 = 39.Approach is straight forward. Simply find the max prime factor, and calculate the sum and return.Example#include #include using namespace std; int maxPrimeFact(int n){    int num = n;    int maxPrime = -1;    while (n % 2 == 0) {       maxPrime = 2;       n /= 2;    }    for (int i = 3; i 2)    maxPrime = n;    return maxPrime; } int getRes(int n) {    int sum = maxPrimeFact(n) + n;    return sum; } int main() {    int n = 26;    cout

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Greatest Common Divisor of Strings in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 3K+ Views

Suppose there are two strings A and B. We can say that A is divisible by B, when A is created by concatenating B one or more times. So if A = “abcabc”, and B = “abc”, then A is divisible by B. In this section, we will see what is the greatest common divisor of a String. So return the largest string that divides both of the strings. So if two strings are “ABABAB”, and “ABAB”, then GCD will be “AB”To solve this, we will follow these steps −temp := shorter string between A and Bm := length of ...

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Occurrences After Bigram in Python

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 213 Views

Suppose there are words given. These are first and second, consider occurrences in some text of the form "first second third", here second comes immediately after the first, and third comes immediately after the second.For each such cases, add "third" into the answer, and show the answer. So if the text is like “lina is a good girl she is a good singer”, first = “a”, second = “good”, the answer will be [girl, singer]To solve this, we will follow these steps −text := split the string by spacesres is an empty listfor i := 0 to size of text ...

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Find the center of the circle using endpoints of diameter in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 249 Views

Suppose we have two endpoints of diameter of a circle. These are (x1, y1) and (x2, y2), we have to find the center of the circle. So if two points are (-9, 3) and (5, -7), then the center is at location (-2, -2).We know that the mid points of two points are −$$(x_{m},y_{m})=\left(\frac{(x_{1}+x_{2})}{2},\frac{(y_{1}+y_{2})}{2}\right)$$Example#include using namespace std; class point{    public:       float x, y;       point(float x, float y){          this->x = x;          this->y = y;       }       void display(){          cout

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Find the closest and smaller tidy number in C++

Arnab Chakraborty
Arnab Chakraborty
Updated on 11-Mar-2026 169 Views

Suppose we have a number n, we have to find the closest and smaller tidy number of n. So a number is called tidy number, if all of its digits are sorted in non-decreasing order. So if the number is 45000, then the nearest and smaller tidy number will be 44999.To solve this problem, we will traverse the number from end, when the tidy property is violated, then we reduce digit by 1, and make all subsequent digit as 9.Example#include using namespace std; string tidyNum(string number) {    for (int i = number.length()-2; i >= 0; i--) {     ...

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