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Articles by Arnab Chakraborty
Page 164 of 377
Minimum Distance to Type a Word Using Two Fingers in C++
Suppose we have a keyboard layout like below −ABCDEFGHIJKLMNOPQRSTUVWXYZWhere each English uppercase letter is located at some coordinate, as an example, the letter A is placed at (0, 0), the letter B is placed at (0, 1), the letter P is placed at (2, 3) and the letter Z is placed at (4, 1). Now if we have a word, we have to find the minimum total distance to type such string using only two fingers. The distance between two places (x1, y1) and (x2, y2) is |x1 - x2| + |y1 - y2|. And we can start from any ...
Read MoreMinimum Number of Taps to Open to Water a Garden in C++
Suppose there is a one-dimensional garden on the x-axis. The starting position of the garden is 0, and ending position is n. There are n + 1 taps located at points [0, 1, ..., n] in the garden. If we have an integer n and an integer array ranges of length n + 1 where ranges[i] is the i-th tap can water the area [i - ranges[i], i + ranges[i]] when that area is open.We have to find the minimum number of taps that should be open to water the whole garden, if there is no possible solution, then return ...
Read MoreMaximal Rectangle in C++
Suppose we have a 2D binary matrix where 0s and 1 values are present. We have to find the largest rectangle containing only 1s and return its area.To solve this, we will follow these steps−Define a function called getAns, this will take array acreate stack st, i := 0, ans := 0while i < size of a, thenif stack is empty or a[i] >= top of stack, then insert i into st, increase i by 1otherwise −height := a[top of stack], delete from stackwidth := i when stack is empty, otherwise i – top of st – 1area := height ...
Read MoreInterleaving String in C++
Suppose we have three strings s1, s2 and s3. Then check whether s3 is formed by interleaving s1 and s2 or not. So if the strings are “aabcc”, s2 = “dbbca”, and s3 is “aadbbcbcac”, then the result will be true.To solve this, we will follow these steps −Define one method called solve(), this will take s1, s2, s3 and one 3d array dp, then i, j, kif i = 0 and j = 0 and k = 0, then return trueif dp[i, j, k] is not -1, then return dp[i, j, k]ans := falseif j > 0 and k ...
Read MoreMinimum Difficulty of a Job Schedule in C++
Suppose we want to schedule a list of tasks in d days. The tasks are dependent so, to work on the i-th task, we have to finish all the tasks j where 0 0, then −return 1^6if dp[idx, k] is not equal to -1, then −return dp[idx, k]maxVal := 0ret := inffor initialize i := idx, when i < size of v, update (increase i by 1), do −maxVal := maximum of v[i] and maxValret := minimum of ret and maxVal + solve(v, i + 1, k - 1, dp)dp[idx, k] := retreturn retFrom the main method do the ...
Read MoreNew 21 Game in C++
Suppose Rima plays the following game, that is loosely based on the card game "21". So Rima starts with 0 points, and draws numbers while she has less than K points. Now, during each draw, she gains an integer number of points randomly from the range [1, W], where W is given, and that is an integer. Now each draw is independent and the outcomes have equal probabilities. Rima stops drawing numbers when she gets K or more points. We have to find the probability that she has N or less points?So if N = 6, K is 1 and ...
Read MoreRecover Binary Search Tree in C++
Suppose we have one binary search tree, now consider two elements of this BST is swapped, so we have to recover this binary search tree.So if the given tree is like below (first one), the recovered tree will be (second one) −To solve this, we will follow these steps −Define some prev, first, second reference for nodesDefine one method called findProblem(), this will take nodeif node is null, then returncall findProblem(left of node)if prev is not null and value of prev > value of node, thenif first is null, then first = prevsecond := nodeprev := nodecall findProblem(right of node)From ...
Read MoreJump Game V in C++
Suppose we have an array of integers called arr and an integer d. In one step we can jump from index i to −i + x where: i + x < n and x in range 1 to d.i - x where: i - x >= 0 and x in range 1 to d.Here n is the size of array. In addition, we can only jump from index i to index j when arr[i] > arr[j] and arr[i] > arr[k] for all indices k between i and j. We can choose any index of the array and start the jumping. ...
Read MoreIndex Pairs of a String in Python
Suppose we have a text string and words (a list of strings), we have to find all index pairs [i, j] such that the substring text[i]...text[j] is in the list of words. So if the string is like “ababa” and words array is like [“aba”, “ab”], then the output will be [[0, 1], [0, 2], [2, 3], [2, 4]]. One thing we can notice, that the matches can overlap, the “aba” is matched in [0, 2] and [2, 4].To solve this, we will follow these steps −res := an empty listfor i in range 0 to a length of stringfor ...
Read MoreTwo Sum Less Than K in Python
Suppose we have an array A of integers and another integer K is given. We have to find the maximum S such that there exists i < j with A[i] + A[j] = S and S < K. If there is no i, j exists satisfying this equation, then return -1. So for example if A = [34, 23, 1, 24, 75, 33, 54, 8] and K = 60, then the output will be 58, as we can use 34 and 24 to sum 58, which is less than 60.To solve this, we will follow these steps −res = - ...
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