Timespan shows the length of time.To get the maximum value of TimeSpan, use the following property.TimeSpan.MaxValueExample Live Demousing System; using System.Linq; public class Demo {    public static void Main() {       Console.WriteLine(TimeSpan.MaxValue);    } }Output10675199.02:48:05.4775807

Timespan shows the length of time.To get the minimum value of TimeSpan, use the following property.TimeSpan.MinValueExample Live Demousing System; using System.Linq; public class Demo {    public static void Main() {       Console.WriteLine(TimeSpan.MinValue);    } }Output-10675199.02:48:05.4775808

Use the TakeLast() method to return elements from the end of an array.Let us first declare and initialize an array.int[] prod = { 110, 290, 340, 540, 456, 698, 765, 789};Now, let’s get the last three elements.IEnumerable units = prod.AsQueryable().TakeLast(3);Let us see the complete code.Example Live Demousing System; using System.Linq; using System.Collections.Generic; public class Demo {    public static void Main() {       int[] prod = { 110, 290, 340, 540, 456, 698, 765, 789};       // value of last three products       IEnumerable units = prod.AsQueryable().TakeLast(3);       foreach (int res in units) {          Console.WriteLine(res);       }    } }Output698 765 789

To set the max value for a Date, use the DateTime property MaxValue.DateTime max = DateTime.MaxValue;Now, display the value of max to get the maximum value of a date as shown below.Example Live Demousing System; using System.Linq; public class Demo {    public static void Main() {       DateTime max = DateTime.MaxValue;       Console.WriteLine(max);    } }Output12/31/9999 11:59:59 PM

The Generate Date Short Time format specifier is a combination of the short date ("d") and short time ("t") patterns, separated by a space.Set a date using DateTime.DateTime dt = new DateTime(2018, 10, 2, 7, 59, 20);Now, use the (“g”) format specifier.dt.ToString("g", DateTimeFormatInfo.InvariantInfo));Example Live Demousing System; using System.Globalization; class Demo {    static void Main() {       DateTime dt = new DateTime(2018, 10, 2, 7, 59, 20);       Console.WriteLine(dt.ToString("g", DateTimeFormatInfo.InvariantInfo));       Console.WriteLine(dt.ToString("g", CultureInfo.CreateSpecificCulture("en-us")));    } }Output10/02/2018 07:59 10/2/2018 7:59 AM

Set a DateTime to its minimum value.DateTime.MinValue;The above will display the minimum value i.e.1/1/0001Let us see how to display the minimum value and avoid adding null to a date to initialize it as empty.Example Live Demousing System; using System.Linq; public class Demo {    public static void Main() {       DateTime dt = DateTime.MinValue;       Console.WriteLine(dt);    } }Output1/1/0001 12:00:00 AM

To display current month, firstly use “Now“ to get the current date.DateTime dt = DateTime.Now;Now, use the Month property to get the current month.dt.MonthLet us see the complete code.Example Live Demousing System; using System.Linq; public class Demo {    public static void Main() {       DateTime dt = DateTime.Now;       Console.WriteLine(dt.Month);    } }Output9To display current month’s name.Example Live Demousing System; using System.Linq; public class Demo {    public static void Main() {       DateTime dt = DateTime.Now;       Console.WriteLine(dt.ToString("MMM"));    } }OutputSep

Use DateTime. DayOfWeek property to display the current day of week.DayOfWeek wk = DateTime.Today.DayOfWeek;Now, displaying “wk” would give you the current day of the week.Let us see the complete code to get the current day of week.Example Live Demousing System; using System.Linq; public class Demo {    public static void Main() {       DayOfWeek wk = DateTime.Today.DayOfWeek;       Console.WriteLine(wk);    } }OutputWednesday

Use All() Method to check whether the elements of a sequence satisfy a condition or not. Even if one of the element do not satisfy the set condition, the All() method returns False.To set conditions, use Lambda Expressions. Below shows a condition to check whether all the elements are greater than 20 or not.myArr.AsQueryable().All(val => val > 20);Let us see an example.Example Live Demousing System; using System.Linq; class Demo {    static void Main() {       int[] myArr = {7, 15, 22, 30, 40};       // checking if all the array elements are greater than 20       bool res = myArr.AsQueryable().All(val => val > 20);       Console.WriteLine(res);    } }OutputFalse

Use the AsEnumerable() method to cast a type to its IEnumerable equivalent. It is an extension method.For our example, we have set an array.int[] myArr = new int[10]; myArr[0] = 1; myArr[1] = 2; myArr[2] = 3; myArr[3] = 4; myArr[4] = 5;Now, we have used the AsEnumerable() method to cast.myArr.AsEnumerable();Example Live Demousing System; using System.Linq; class Demo {    static void Main() {       int[] myArr = new int[10];       myArr[0] = 1;       myArr[1] = 2;       myArr[2] = 3;       myArr[3] = 4;       myArr[4] = 5;       myArr[5] = 6;       myArr[6] = 7;       myArr[7] = 8;       myArr[8] = 9;       myArr[9] = 10;       // AsEnumerable       var a = myArr.AsEnumerable();       // Displaying       foreach (var item in a) {          Console.WriteLine(item);       }    } }Output1 2 3 4 5 6 7 8 9 10