The exception thrown when a null reference is passed to a method that does not accept it as a valid argument.Let us see an example.When we set a null parameter to int.Parse() method, then ArgumentNullException is thrown as shown below −Exampleusing System; class Demo {    static void Main() {       string val = null;       int res = int.Parse(val); // error is thrown    } }OutputThe following error is thrown when the above program is compiled since we have passed a null value.Unhandled Exception: System.ArgumentNullException: Value cannot be null.

To get the bounds of a three-dimensional array, use the GetUpperBound() GetLowerBound() methods in C#.The parameter to be set under these methods is the dimensions i.e.Let’s say our array is −int[, , ] arr = new int[3, 4, 5];For a three-dimensional arrays, dimension 0.arr.GetUpperBound(0) arr.GetLowerBound(0)For a three-dimensional arrays, dimension 1.arr.GetUpperBound(1) arr.GetLowerBound(1)For a three-dimensional arrays, dimension 2.arr.GetUpperBound(2) arr.GetLowerBound(2)Let us see the entire example.Example Live Demousing System; class Program {    static void Main() {       int[, , ] arr = new int[3, 4, 5];       Console.WriteLine("Dimension 0 Upper Bound: {0}", arr.GetUpperBound(0).ToString());       Console.WriteLine("Dimension 0 Lower Bound: ... Read More

Let’s say our three-dimensional array is −int[,,] arr = new int[3,4,5];To get the height and width i.e. the rows and columns.Array.GetLength(0) – for rows Array.GetLength(1) – for columnsExample Live Demousing System; class Program {    static void Main() {       int[,,] arr = new int[3,4,5];       Console.WriteLine(arr.GetLength(0));       Console.WriteLine(arr.GetLength(1));       Console.WriteLine(arr.GetLength(2));    } }Output3 4 5

To get the rank of a three-dimensional array, use the Rank property.Set a three-dimensional array.int[,,] arr = new int[3,4,5]Now get the rank.arr.RankLet us see the complete code.Exampleusing System; class Program {    static void Main() {       int[,,] arr = new int[3,4,5]       Console.WriteLine("Dimensions of Array : " + arr.Rank);    } }

Merge sequences using predicate with Zip method.Here are our arrays to be merged.int[] intArray = { 10, 20, 30, 40 }; string[] stringArray = { "Jack", "Tim", "Henry", "Tom" };Now let’s use the Zip method to merge both the arrays.intArray.AsQueryable().Zip(stringArray, (one, two) => one + " " + two)The following is our code.Example Live Demousing System; using System.Linq; using System.Collections.Generic; public class Demo {    public static void Main() {       int[] intArray = { 10, 20, 30, 40 };       string[] stringArray = { "Jack", "Tim", "Henry", "Tom" };       var mergedSeq = intArray.AsQueryable().Zip(stringArray, (one, two) => one + " " + two);       foreach (var ele in mergedSeq)       Console.WriteLine(ele);    } }Output10 Jack 20 Tim 30 Henry 40 Tom

Use the LastorDefault() method to return the last element of a sequence or a default value if element isn’t there.The following is our empty list.List val = new List { };Now the following will not be able to display the last element since the list is empty. Therefore, the default would get display and error won’t be shown.val.AsQueryable().LastOrDefault();The following is the code.Example Live Demousing System; using System.Collections.Generic; using System.Linq; class Demo {    static void Main() {       List val = new List { };       double d = val.AsQueryable().LastOrDefault();       Console.WriteLine("Default Value = "+d); ... Read More

Perform Union on two sequences using the Queryable Union method.The following are our arrays.int[] arr1 = { 29, 40, 15, 55, 70, 30, 90 }; int[] arr2 = { 30, 36, 40, 18, 15, 55, 75 };Now, get the Union of the arrays using the Union method.arr1.AsQueryable().Union(arr2);Example Live Demousing System; using System.Linq; using System.Collections.Generic; public class Demo {    public static void Main() {       int[] arr1 = { 29, 40, 15, 55, 70, 30, 90 };       int[] arr2 = { 30, 36, 40, 18, 15, 55, 75 };       IEnumerable res = arr1.AsQueryable().Union(arr2);       foreach (int a in res)       Console.WriteLine("{0} ", a);    } }Output29 40 15 55 70 30 90 36 18 75

Add a node before a given node in C# using the AddBefore() method.Our LinkedList with string nodes.string [] students = {"Henry", "David", "Tom"}; LinkedList list = new LinkedList(students);Now, let’s add node at the end.// adding a node at the end var newNode = list.AddLast("Brad");Use AddBefore() method to add a node before the node added above.list.AddBefore(newNode, "Emma");Example Live Demousing System; using System.Collections.Generic; class Demo {    static void Main() {       string [] students = {"Henry", "David", "Tom"};       LinkedList list = new LinkedList(students);       foreach (var stu in list) {          Console.WriteLine(stu); ... Read More

Orders elements in a sequence using ThenBy() method.We have the following string array.string[] str = { "AAA", "AAAA", "A", "AAAAA", "AAAAAAAAA" };Now, use Lambda Expressions and set a condition inside the ThenBy() method to sort the strings according to the number of characters they have.IEnumerable res = str.AsQueryable() .OrderBy(alp => alp.Length).ThenBy(alp => alp);Example Live Demousing System; using System.Linq; using System.Collections.Generic; public class Demo {    public static void Main() {       string[] str = { "AAA", "AAAA", "A", "AAAAA", "AAAAAAAAA" };       IEnumerable res = str.AsQueryable() .OrderBy(alp => alp.Length).ThenBy(alp => alp);       foreach (string arr ... Read More

To orders elements in a sequence in descending order, use ThenBy() and OrderByDescending.This is our string array.string[] myStr = { "Keyboard", "Laptop", "Mouse", "Monitor" };Now, use OrderByDescending to order element in Descending order. Inside that calculate the length of each string and use Lambda Expressions as well.IEnumerable res = myStr.AsQueryable().OrderByDescending(ch => ch.Length).ThenBy(ch => ch);The following is the example discussed above.Example Live Demousing System; using System.Linq; using System.Collections.Generic; public class Demo {    public static void Main() {       string[] myStr = { "Keyboard", "Laptop", "Mouse", "Monitor" };       IEnumerable res = myStr.AsQueryable().OrderByDescending(ch => ch.Length).ThenBy(ch => ch);   ... Read More