To update multiple elements, use $[]. The $[] is an all positional operator indicating that the update operator should modify all elements in the specified array field.Let us first create a collection with documents −> db.demo385.insertOne({"ServerLogs": [ ...       { ...          "status":"InActive" ...       }, ...       { ...          "status":"InActive" ...       }, ...       { ...          "status":"InActive" ...       } ...    ] ... } ... ); {    "acknowledged" : true,    "insertedId" : ... Read More

Projection means only selected field must be visible. Set the field to 1, if you want to make it visible.Let us first create a collection with documents −> db.demo384.insertOne({"StudentName":"Chris Brown", "StudentCountryName":"US"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5b67a022064be7ab44e7f2") } > db.demo384.insertOne({"StudentName":"David Miller", "StudentCountryName":"AUS"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5b67ab22064be7ab44e7f3") } > db.demo384.insertOne({"StudentName":"John Doe", "StudentCountryName":"UK"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5b67b422064be7ab44e7f4") }Display all documents from a collection with the help of find() method −> db.demo384.find();This will produce the following output −{ "_id" : ObjectId("5e5b67a022064be7ab44e7f2"), "StudentName" : "Chris Brown", "StudentCountryName" : "US" } { ... Read More

To filter the logs containing the word “work” , use aggregate() along with $filter. Let us first create a collection with documents −> db.demo383.insertOne( ...    { ...       "ServerName":"Jboss", ...       "ServerLogs": [ ...          { ...             "status":"Working" ...          }, ...          { ...             "status":"Stop" ...          }, ...          { ...             "status":"Worked" ...          } ...   ... Read More

For this, use $project and in that, $size to get the length. Let us first create a collection with documents −> db.demo382.insertOne( ...    { ... ...       "Name" : "David", ...       "details" : [ ...          { ...             "SubjectName":"MySQL" ...          }, ...          { ...             "SubjectName":"MongoDB" ...          }, ...          { ...             "SubjectName":"Java" ...          } ... Read More

For this, use $indexOfArray. Let us first create a collection with documents −> db.demo381.insertOne({"Values":[10, 40, 60, 30, 60]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5b59f72ae06a1609a00b15") } > db.demo381.insertOne({"Values":[100, 500, 700, 500, 800]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5b59f72ae06a1609a00b16") } > db.demo381.insertOne({"Values":[20, 40, 30, 10, 60]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5b59f72ae06a1609a00b17") }Display all documents from a collection with the help of find() method −> db.demo381.find();This will produce the following output −{ "_id" : ObjectId("5e5b59f72ae06a1609a00b15"), "Values" : [ 10, 40, 60, 30, 60 ] } { "_id" : ObjectId("5e5b59f72ae06a1609a00b16"), "Values" : [ 100, ... Read More

The $addToSet operator adds a value to an array unless the value is already present, in which case $addToSet does nothing to that array.Let us first create a collection with documents −> db.demo380.insertOne({ ... ...    "details" : [ ...       { ...          "Name" : "Chris", ...          "details1" : [ ] ...       }, ...       { ...          "Name" : "David", ...          "details1" : [ ] ...       } ...    ] ... } ... ); ... Read More

For projection on specific nested properties, use aggregate() in MongoDB. Let us first create a collection with documents −> db.demo379.insertOne( ...    { ...       "details1" : { ...          "details2" : { ...             "details3" : { ...                "10" : "John", ...                "50" : "Chris", ...                "40" : "David", ...                "30":"Mike" ...             } ...   ... Read More

To manipulate subdocuments, use dot(.) notation in MongoDB. Let us first create a collection with documents −> db.demo378.insertOne( ...    { ...       Name: 'Chris', ...       details:[ ...          {id:101, Score:56}, ...          {id:102, Score:78} ...       ] ...    } ... ); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5a758a2ae06a1609a00b0f") }Display all documents from a collection with the help of find() method −> db.demo378.find();This will produce the following output −{    "_id" : ObjectId("5e5a758a2ae06a1609a00b0f"), "Name" : "Chris", "details" : [       { "id" ... Read More

To concatenate, use $concat in MongoDB aggregate(). Let us first create a collection with documents −> db.demo377.insertOne({"ListOfIds":[1001, 1002, 1003, 1004, 1005, 1006, 1007]}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e5a73462ae06a1609a00b0e") }Display all documents from a collection with the help of find() method −> db.demo377.find().pretty();This will produce the following output −{    "_id" : ObjectId("5e5a73462ae06a1609a00b0e"),    "ListOfIds" : [       1001,       1002,       1003,       1004,       1005,       1006,       1007    ] }Following is the query to concatenate an array of integer ... Read More

To update documents, you cannot use aggregation pipeline. You can use update(). Let us first create a collection with documents −> db.demo376.insertOne( ...    { ... ...       "id" :101, ... ...       "details" : [ ...          { ...             Name:"Chris", ...             Age:21, ...             Score:45 ...          }, ...          { ...             Name:"David", ...             Age:23, ...   ... Read More