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Microprocessor Articles
Page 37 of 42
8085 Program to convert a two-digit BCD to binary
In this program we will see how to convert BCD numbers to binary equivalent.Problem StatementA BCD number is stored at location 802BH. Convert the number into its binary equivalent andstore it to the memory location 802CH.DiscussionIn this problem we are taking a BCD number from the memory and converting it to its binaryequivalent. At first we are cutting each nibble of the input. So ifthe input is 52 (0101 0010) then we can simply cut it by masking the number by 0FH and F0H. When the Higher order nibble is cut, thenrotate it to the left four times to transfer ...
Read More8085 Program to convert an 8-bit binary to BCD
In this program we will see how to convert binary numbers to its BCD equivalent.Problem StatementA binary number is store dat location 800H. Convert the number into its BCD equivalent and store it to the memory location 8050H.DiscussionHere we are taking a number from the memory, and initializing it as a counter. Now in each step of this counter we are incrementing the number by 1, and adjust the decimal value. By this process we are finding the BCD value of binary number or hexadecimal number.We can use INR instruction to increment the counter in this case but this instruction ...
Read More8085 Program to check for palindrome
Now let us see a program of Intel 8085 Microprocessor. This program will convert ASCII to binary values.Problem StatementWrite 8085 Assembly language program to check whether a bit pattern is palindrome or not.DiscussionIn this program we are taking the number from location 8000H. The program will return 00H if the number is not palindrome, otherwise it will return FFH.Let the Input is 18H so the binary value is (0001 1000) this is a palindrome. The number 52H(0101 0010) it is not a palindrome.In this problem we are taking the first number into accumulator, then shifting it to the left. When ...
Read More8085 Program to multiply two 16-bit binary numbers
Now let us see a program of Intel 8085 Microprocessor. This program will calculate the multiplication of two 16-bit numbers.Problem StatementWrite 8085 Assembly language program to multiply two 16-bit numbers stored at 8000H -8001H and 8002H - 8003H.DiscussionThis program takes the 16 bit data from memory location 8000H – 8001Hand 8002H – 8003H. The 32 bit results are stored at location 8050H– 8053H.Here we have tested with two 16 bit numbers. The results are as follows 1111H × 1111H = 01234321H 1C24H × 0752H = 00CDFF88HInputfirst inputAddressData......800011800111800211800311......second input AddressData......80002480011C800252800307......Flow DiagramProgramAddressHEXCodesLabelsMnemonicsCommentsF00031, 00, 20LXI SP, 2000H InitializeStack pointerF0032A, 00, ...
Read MoreProgramming the 8253
According to the microprocessor point of view, the 8253 is designed and has some specialty port chip I/O. We don't use it for interfering the I/O devices. For performing the application of time it is used. 8253 has the addressed A1 and A0 input pins.The counters have width of 16 bits. If they were 8-bits wide, the delay in time that would be generated is very small. The Least Significant Byte and the Most Significant Byte of a counter is selected by using the same address of the port.The processor here writes to the control port to configure the working of ...
Read MoreProgram to Find the largest number in an array of data in 8085 Microprocessor
In this program we will see how to find the largest number from a block of bytes using 8085.Problem StatementWrite 8085 Assembly language program to find the largest number from a block of bytes.DiscussionIn this program the data are stored at location 8001H onwards. The 8000H is containing the size of the block. After executing this program, it will return the largest number and store it at location 9000H.Logic is simple, we are taking the first number at register B to start the job. In each iteration we are getting the number from memory and storing it into register A. ...
Read MoreProgram to Find the smallest number in an array of data in 8085 Microprocessor
In this program we will see how to find the smallest number from a block of bytes using 8085.Problem StatementWrite 8085 Assembly language program to find the smallest number from a block of bytes.DiscussionIn this program the data are stored at location 8001H onwards. The 8000H is containing the size of the block. After executing this program, it will return the smallest number and store it at location 9000H.Logic is simple, we are taking the first number at register B to start the job. In each iteration we are getting the number from memory and storing it into register A. ...
Read More8085 program to add two 16 bit numbers
In this program we will see how to add two 16-bit numbers.Problem StatementWrite8085 Assembly language program to add two 16-bit number stored in memory location 8000H – 8001H and 8002H – 8003H.DiscussionIn this program we are pointing the operand addresses using HL and DE register pair. Then adding LSBytes by ADD operator, and after that adding MSBytes using ADC operator to consider the carry flag result. The 16-bit result will be stored at BC register, and by checking the carry bit after addition we can simply put 1 into memory.We are taking two numbersBCAD + FE2D = 1BADAInputAddressData......8000AD8001BC80022D8003FE......Flow DiagramProgramAddressHEX CodesLabelsMnemonicsCommentsF00021, ...
Read More8085 program to add 2-BCD numbers
In this program we will see how to add two 8-bit BCD numbers.Problem StatementWrite 8085 Assembly language program to add two 8-bit BCD number stored in memory location 8000H – 8001H.DiscussionThis task is too simple. Here we are taking the numbers from memory and after adding we need to put DAA instruction to adjust the accumulator content to decimal form. The DAA will check the AC and CY flags to adjust a number to its decimal form.InputAddressData......800099800125......Flow DiagramProgramAddressHEX CodesLabelsMnemonicsCommentsF00021, 00, 80LXI H, 8000HPoint to first operandF0037EMOV A, MLoad A with first operandF00423INX HPoint to next operandF00586ADD MAdd Acc and memory ...
Read More8085 program to find the sum of first n natural numbers
In this program we will see how to add first n natural numbers.Problem StatementWrite 8085 Assembly language program to add first N natural numbers. The value of N is provided.DiscussionWe are getting the value of N from memory location 8000H. We are using the number N as count variable, in each step we are calculating (A + Count) value, and store them into A. After adding them, the count value is decreased, thus the total series is completed.If the number is 23H(35D), then the sum will be (35*36)/2 = 630 (276H)InputAddressData......800023......Flow DiagramProgramAddressHEX CodesLabelsMnemonicsCommentsF00021, 00, 80LXI H, 8000HPoint to get the ...
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