Suppose there is a circle, and there are n petrol pumps on the circle. We have two sets of data like −The amount of petrol that every petrol pump hasDistance from one petrol pump to anotherCalculate the first point, from where a truck will be able to complete the circle. Assume for 1 liter petrol, the truck can go 1 unit of distance. Suppose there are four petrol pumps, and the amount of petrol, and distance from the next petrol pump is as like [(4, 6), (6, 5), (7, 3), (4, 5)], the first point from where truck can make ... Read More

Suppose there are N stations in the straight line. Each of them has same non-negative power of radiation power. Every station can increase the radiation power of its neighboring stations in the following way.Suppose the station i with radiation power R, will increase (i – 1)th station’s radiation power, by R-1, (i - 2)th station’s radiation power by R-2, and will increase (i + 1)th station’s radiation power, by R-1, (i + 2)th station’s radiation power by R-2. So on. So for example, if the array is like Arr = [1, 2, 3], then the output will be 3, 4, ... Read More

Suppose we have an array A with n elements. We have to find the maximum number of the contiguous even numbers in the given array. So if the array is like A = [1, 2, 3, 4, 6, 8, 7], then the count will be 3.We can solve this easily. We need two count variables one is max_current, and another is max_till_now. If an even number is found, then increase max_current, then compare it with max_till_now. Every time an odd element is found reset max_count to 0.Example Live Demo#include using namespace std; int maxEvenContiguous(int arr[], int n) {    int max_current ... Read More

Suppose we have an ellipse, with major and minor axis length 2a & 2b. We have to find the area of the largest circle that can be inscribed in it. So if the a = 5 and b = 3, then area will be 28.2734From the we can see that the radius of the maximum area circle inscribed in an ellipse will be the minor axis ‘b’. So the area will be A = π*b*bExample Live Demo#include using namespace std; double inscribedCircleArea(double b) {    double area = 3.1415 * b * b;    return area; } int main() {    double a = 10, b = 8;    cout

Suppose we have a positive integer L, which represents the number of levels in a perfect binary tree. The leaf nodes in this perfect binary tree are numbered starting from 1 to n. Where the n is number of leaf nodes. The parent node is the sum of children. Our task is to write a program to print the sum of all of the nodes of this perfect binary tree. So if the tree is like below −So total sum is 30.If we see closer, we need to find the sum of all of the nodes. As the leaf nodes ... Read More

Suppose we have two sorted arrays arr1 and arr2, there sizes are m and n respectively. We have to find relative complement of two arrays. It means that we need to find all those elements which are present in arr1, but not in arr2. So if the arrays are like A = [3, 6, 10, 12, 15], and B = [1, 3, 5, 10, 16], then result will be [6, 12, 15]To solve this, we can use the set_difference function. As the problem is basically set difference operation.Example Live Demo#include #include #include using namespace std; int main() {    int first[] ... Read More

Consider there is a special family of doctors and engineers. There are some rules, these are like below −Everybody has two childrenFirst child of an engineer is an engineer, second child is doctorFirst child of a doctor is a doctor, second child is an engineerAll generations of doctors and engineers starts with engineerSo if we want to get result for level 4 and pos 2, then result will be DoctorThe idea is simple. Profession of a person depends on following two.Profession of the parent.Position of node: When the position of a node is odd, then its profession is same as ... Read More

Suppose we have such amount, and we have to find the minimum number of notes of different denominations, that sum up to the given amount. Start from highest denomination notes, try to find as many notes possible for given amount. Here the assumption is that we have infinite amount of {2000, 500, 200, 100, 50, 20, 10, 5, 2, 1}. So if the amount is say 800, then notes will be 500, 200, 100.Here we will use the greedy approach to solve this problem.Example Live Demo#include using namespace std; void countNotes(int amount) {    int notes[10] = { 2000, 500, 200, ... Read More

Suppose we want to make a stack that can store the maximum element in the stack. And we can get it in O(1) time. The constraint is that, it should not use any additional space, so O(1) extra space.We can make one user-defined stack, that will store the max value, when one operation is performed, like pop or peek, then the max will be returned. For peek operation, return the maximum of stack top and the max element, for pop operation, when the top element is larger, then print it and update max as 2*max – top_element. otherwise return top_element. ... Read More

Suppose we have one encoded string, where repetitions of substrings are represented as substring followed by count of substrings. So if the string is like ab2cd2, it indicates ababcdcd, and if k = 4, then it will return kth character, that is b here.To solve this, we initially take empty decrypted string then decompress the string by reading substring and its frequency one by one. Then append current substring in the decrypted string by its frequency. We will repeat this process till the string has exhausted, and print the Kth character from decrypted string.Example Live Demo#include using namespace std; char findKthCharacter(string ... Read More